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Zinaida [17]
3 years ago
10

Francine has a picture whose length is its width. She wants to enlarge the picture to have an area of 192 in2. What will the dim

ensions of the enlarged picture be? Model the scenario and solve. Then, explain in at least one sentence your solution and include the reasonableness of your solution.
Mathematics
1 answer:
MaRussiya [10]3 years ago
6 0
The answer:

<span>according to the question the length is its width, that means 
w=l
</span><span>She wants to enlarge the picture to have an area of 192 in2,
that means   Area = </span>wxl = 192 in²
so, since w=l, we can write that Area = wxl =w²=l²= 192 in², this implies:
w=sqrt (192) = 13.85 in

finally the width w = 13.85, and the length l=  13.85 because w=l
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jenyasd209 [6]

Answer:

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Whats 4(d+2)-2d=3(2+d)
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Simplify:

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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

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δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) =  δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

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6 0
4 years ago
Function g is defined below.
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4. y=f(x)+a is translation a units up;

Since g(x)=f(x+2)-5, then firstly you have to translate the graph of function y=f(x) two units left and secondly 5 units down.


6 0
4 years ago
Read 2 more answers
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Mama L [17]
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7 0
3 years ago
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