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8090 [49]
3 years ago
15

Can the numeric value for the area of a circle ever equal the numeric value for the circumference of the same circle? Explain

Mathematics
1 answer:
Vlad [161]3 years ago
4 0
C=2pr, a=pr^2 

pr^2=2pr 

<span>r=2</span>
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What is the median for the set of data shown
klemol [59]

Answer: OPTION C

Step-by-step explanation:

 By definition, the median is the middle number in the set.

Therefore, keeping the definition  above on mind, to solve this problem the numbers must be arranged from least to greastest. In the figure shown in the problem, you can see that they are already arranged in this order. Therefore, the middle number in the set is:

14, 28, 33, 42, 53, 81, 97

Then, you can conclude that the median is: 42.

Therefore, the answer is the Option C.

8 0
3 years ago
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Write the following as an algebraic expression: 7 less than 3 times x.
Lady bird [3.3K]

Answer:

3-7x

Step-by-step explanation:

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3 years ago
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An ipad is worth R1200, excluding 15% VAT. What is the selling price of the ipad including VAT
alukav5142 [94]

Answer:

R1,380

Step-by-step explanation:

The price of the iPad without VAT is R1200

We calculate 15% to get;

=  \frac{15}{100}  \times 1200

= 180

Now the selling price of the iPad including VAT

1200 + 180

= 1380

Therefore, the selling price of the ipad including VAT is R1380

7 0
3 years ago
What is 50 divide by 25 times 2 divided by 5 ?
klemol [59]
0.8 i think I’m not sure .
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3 years ago
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If sinA+cosecA=3 find the value of sin2A+cosec2A​
Irina18 [472]

Answer:

\sin 2A + \csc 2A = 2.122

Step-by-step explanation:

Let f(A) = \sin A + \csc A, we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:

\csc A = \frac{1}{\sin A} (1)

\sin^{2}A +\cos^{2}A = 1 (2)

Now we perform the operations: f(A) = 3

\sin A + \csc A = 3

\sin A + \frac{1}{\sin A} = 3

\sin ^{2}A + 1 = 3\cdot \sin A

\sin^{2}A -3\cdot \sin A +1 = 0 (3)

By the quadratic formula, we find the following solutions:

\sin A_{1} \approx 2.618 and \sin A_{2} \approx 0.382

Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

\sin A \approx 0.382

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

A \approx 22.457^{\circ}

Then, the values of the cosine associated with that angle is:

\cos A \approx 0.924

Now, we have that f(A) = \sin 2A +\csc2A, we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used:

\sin 2A = 2\cdot \sin A\cdot \cos A (4)

\csc 2A = \frac{1}{\sin 2A} (5)

f(A) = \sin 2A + \csc 2A

f(A) = \sin 2A +  \frac{1}{\sin 2A}

f(A) = \frac{\sin^{2} 2A+1}{\sin 2A}

f(A) = \frac{4\cdot \sin^{2}A\cdot \cos^{2}A+1}{2\cdot \sin A \cdot \cos A}

If we know that \sin A \approx 0.382 and \cos A \approx 0.924, then the value of the function is:

f(A) = \frac{4\cdot (0.382)^{2}\cdot (0.924)^{2}+1}{2\cdot (0.382)\cdot (0.924)}

f(A) = 2.122

8 0
3 years ago
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