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Rina8888 [55]
3 years ago
6

Rounded to three decimal places, what is the value of r for this data set?

Mathematics
1 answer:
victus00 [196]3 years ago
7 0
I think the answer is B not sure though
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A vase contains 4 pink roses, 8 red roses, and 10 white roses. Two roses are randomly selected from the vase one at a time, with
alisha [4.7K]
There are 22 roses in the vase 
probability of first selecting a red rose = 8/22 = 4/11

P( second one is red) = 7/21 = 1/3

these probabilities are multiplied because the individual picks are independent
 so the answer is 4/11 * 1/4  = 4/33
7 0
3 years ago
What is the fraction of 41.66667
Papessa [141]

Answer:

41\frac{2}{3}  

I hope this helps!

6 0
3 years ago
Read 2 more answers
Thanks for everyone who's helping :) please help for a grade and due today
Komok [63]

Answer:

3 3/4

Step-by-step explanation:

3 0
3 years ago
Help ASAP show work please thanksss!!!!
Llana [10]

Answer:

\displaystyle log_\frac{1}{2}(64)=-6

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

log_b(1) = 0

Logarithm of the base:

log_b(b) = 1

Product rule:

log_b(xy) = log_b(x) + log_b(y)

Division rule:

\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)

Power rule:

log_b(x^n) = n\cdot log_b(x)

Change of base:

\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

\displaystyle log_\frac{1}{2}(64)

Factoring 64=2^6.

\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)

Since

\displaystyle 2=(1/2)^{-1}

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})

Applying the logarithm of the base:

\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}

5 0
2 years ago
What is the equation for x in the diagram ?
mrs_skeptik [129]
I believe the answer is a.
7 0
3 years ago
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