The mean and range for class A are 84.4 and 20 while the mean and range for class B are 83.6 and 8. Class B is more consistant then class A.
<h3>How to calculate the mean?</h3>
We can see from the data that the consistency of class B is more becuase the repeatation of the same score is more in class B then class A and the range of class B is also less then the class A.
It should be noted that mean simply means average. It's the addition of the numbers divided by the total numbers.
In this case, the computation will be:
Class A: Mean = 422/5= 84.4.
Range: 94-74 = 20
Class B: Mean = 418/5 = 83.6.
Range= 88-80 = 8
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answer = 9c²d^8
(3cd^4)^2
=(3)^2 × c^2 × (d^4)^2
=9×c^2×d^8 ----law of indices (a^m)^n = a^mn
=9c²d^8
Step-by-step explanation:
98 = 188t - 16t^2
-16t^2 + 188t = 98
-16t^2 + 188t - 98 = 0
8t^2 - 94t + 49 = 0
Use the quadratic formula with a = 8 , b = -94 , c = 49 to get the solutions
t = [(47 - root 1817) / 8]≈ 0.55
and
t = [(47 + root 1817) / 8] ≈ 11.20
Hello,
The inverse operation's are easy.
is would be h/3-8=19
Hope this helps
Answer:
k= 20
Step-by-step explanation:
You start with this equation:
k-16=4
Add 16 on both sides.
k=4+16
Simply.
k=20
If you want to check your answer, you can just plug 20 into where k is back into the equation:)
Hope this helps!
