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Fudgin [204]
4 years ago
11

What is the answer to this question

Mathematics
1 answer:
BartSMP [9]4 years ago
6 0
It's not B, because undefined is when the slope is a number over zero, but in this case, 0 is over a number, so yeah the answer is c.

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Select the correct button in the table to show the percent decrease from the first number to the second number.
Vitek1552 [10]

340 -255 and 450-351

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3 years ago
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Which table shows a function that is decreasing only over the interval (–1, ∞)?
aleksandr82 [10.1K]

The table that shows a function that is decreasing only over the interval (–1, ∞) is:

A 2-column table with 6 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries negative 1, negative 3, negative 5, negative 2, negative 1, 2.

<h3>When a function is decreasing?</h3>

A function is decreasing if when we increase the value of x, we decrease the value of y, and vice versa.

Decreasing on the (–1, ∞) means that as x increases on the interval, i.e. x = -100, then x = -10, then x = -2, the value of y decreases. The function that follows this pattern only on this interval is:

A 2-column table with 6 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries negative 1, negative 3, negative 5, negative 2, negative 1, 2.

More can be learned about decreasing functions at brainly.com/question/2649645

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3 0
2 years ago
(x+1)^2 . (x^2+1) = 0
Maurinko [17]

Answer:

x^4+2x^3+2x^2+2x+1

Step-by-step explanation:

Given that,

(x+1)^2 . (x^2+1) = 0

We know that, (a+b)^2=a^2+b^2+2ab

So,

(x+1)^2=x^2+1+2x

So,

(x+1)^2 . (x^2+1) = (x^2+1+2x)(x^2+1)\\\\=x^2\times x^2+x^2+2x^3+x^2+1+2x\\\\=x^4+2x^3+2x^2+2x+1

So, the value of the given expression is equal tox^4+2x^3+2x^2+2x+1

8 0
3 years ago
The sum of 11 and the product of 2 and a number r
andrew-mc [135]
Algebraically that would be expressed as 2r + 11

The product of 2 and r is 2r.

The sum of 2r and 11 is 2r + 11
5 0
3 years ago
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A van travelled at an average speed of 65km/hr from town A. A 35 minutes later a car started from town A ans drove along the sam
kobusy [5.1K]

Answer:

91.6 km/h

Step-by-step explanation:

Let v = average speed of van = 65 km/h and v' = average speed of car. Let t be the time the car starts to move. The van started 35 minutes earlier at t' = (t + 35/60) h.

Since distance d = vt where v = velocity and t = time, the distance moved by the van d = vt' = v(t + 35/60) and that moved by the car is d' = v't.

Since the car catches up with the van after it had moved a distance of 130 km,  d = d' = 130 km.

So d = v(t + 0.583)

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130 km = 65 km/h(t + 0.583)

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subtracting 37.895 from both sides, we have

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dividing both sides by 65, we have

t = 92.105/65

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Since d = d' = v't,

v' = d'/t

= 130 km/1.42 h

= 91.55 km/h

≅ 91.6 km/h

So, the average speed of the car is 91.6 km/h

5 0
3 years ago
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