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Diano4ka-milaya [45]
2 years ago
5

PLEASE HELP ASAP!! THIS IS LATE! :(

Mathematics
1 answer:
Svetach [21]2 years ago
4 0

Answer:

States sent representatives to Congress and provided soldiers and some officers to protect the country.

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Ou have found a house that you would like to purchase. The amount of the home is $225,000. You would like to finance the home th
Tpy6a [65]

Answer:

  A.  $22,500

Step-by-step explanation:

10% = 10/100 = 1/10

To divide a decimal number by 10, move the decimal point one place to the left (remove a zero):

  $225000./10 = $22500.0 = $22500

5 0
3 years ago
Help me pls.........!
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If each square represents a square foot half of it would be .5 so then add all of them. The formula for Area is A=l•w and the Area formula for a triangle is A=hbb/2. Hope this helps :)
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3 years ago
Help me with this question
r-ruslan [8.4K]

Answer: 3/2a3

I can't properly write the answer sorry but it's the last one.

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3 years ago
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Could anyone tell me where these numbers would go? domain or range?
Free_Kalibri [48]
Independent, x-coordinate, input, domain.
Dependent, y-coordinate, output, range.

Domain: {0.5, 1, 4, 6, 8}
Range: {1, 1.5, 10, 12, 18}
8 0
3 years ago
Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was
andrezito [222]

Answer:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 100, p = 0.42

92% confidence level

So \alpha = 0.08, z is the value of Z that has a pvalue of 1 - \frac{0.08}{2} = 0.96, so Z = 1.75.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.3336

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.5064

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

4 0
3 years ago
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