Question

(x+1)^2 . (x^2+1) = 0

Answer 1

Answer:

$x^4+2x^3+2x^2+2x+1$

Step-by-step explanation:

Given that,

$(x+1)^2 . (x^2+1) = 0$

We know that, $(a+b)^2=a^2+b^2+2ab$

So,

$(x+1)^2=x^2+1+2x$

So,

$(x+1)^2 . (x^2+1) = (x^2+1+2x)(x^2+1)\\\\=x^2\times x^2+x^2+2x^3+x^2+1+2x\\\\=x^4+2x^3+2x^2+2x+1$

So, the value of the given expression is equal to$x^4+2x^3+2x^2+2x+1$