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3 years ago

(2y-at)(y+2at) find the product

Mathematics

2 answers:

Lunna [17]3 years ago

8 0

$(2y-at)(y+2at)$

$2y^2+4yat-aty-2a^2t^2$

$2y^2+(4yat-aty)-2a^2t^2$

$2y^2+3aty-2a^2t^2$

Fynjy0 [20]3 years ago

6 0

(2y-at)(y+2at)

Answer: −2a^2t^2+3aty+2y^2

I hope this helps

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Is the area of figure 177 ??

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3 years ago

Riley has a farm on a rectangular piece of land that is 200200200 meters wide. This area is divided into two parts: A square are

777dan777 [17]

Answer:

The inequality that models the situation for her to have money to save is

7L² > 3(200L - L²)

On simplifying and solving,

L > 60 meters

Step-by-step explanation:

The length of her farm = L meters

The farm where she grows avocados is of square dimension

Area of the farm = L × L = L²

The piece of land is 200 m wide.

Total area of the piece of land = 200 × L = (200L) m²

If the area of her farm = L²

Area of the side where she lives will be

(Total area of the land) - (Area of the farm)

= (200L - L²)

= L(200 - L)

Every week, Riley spends $3 per square meter on the area where she lives, and earns $7 per square meter from the area where she grows avocados.

Total amount she earns from the side she grows the avocados = 7 × L² = 7L²

Total amount she spends on the side where she lives = 3 × (200L - L²) = 3(200L - L²)

For her to save money, the amount she earns must be greater than the amount she spends, hence the inequality had to be

(Amount she earns) > (Amount she spends)

7L² > 3(200L - L²)

To simplify,

7L² > 3L(200 - L)

Since L is always positive, we can divide both sides by L

7L > 3(200 - L)

7L > 600 - 3L

10L > 600

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Hope this Helps!!!

7 0

3 years ago

Select interior, exterior, or on the circle (x - 5) 2 + (y + 3) 2 = 25 for the following point. (2, 3)

lozanna [386]

Standard equation of a circle: (x-h)² + (y-k)² = r² where (h, k) is the center and r is the radius. In the case of our equation here, (x-5)² + (y+3)² = 25, we can conclude that our circle has a center at (5, -3) and a radius of 5 units.

We can use the distance formula with the center (5, -3) and our point (2, 3) to see how far away they are...if the distance between them is less than the radius of the circle, it is on the interior. If it's equal, it's on the circle. If it's greater, it's on the exterior.

Distance = $\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Distance = $\sqrt{(-3-3)^2+(5-2)^2}$

Distance = $\sqrt{(-6)^2+3^2}$

Distance = $\sqrt{36+9}$

Distance = $\sqrt{45}\approx6.7082$

$6.7082>5,\ so\ (2,3)\ is\ on\ the\ \boxed{exterior}$

8 0

3 years ago