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3 years ago

HELP PLEASE!!! URGENT!!!

1 answer:

3 0

F(x) = 3x + 7.....g(x) = 4x - 2

A. (f + g)(x)
3x + 7 + 4x - 2
7x + 5 <====

B. (f * g)(x)
(3x + 7)(4x - 2) =
3x(4x - 2) + 7(4x - 2) =
12x^2 - 6x + 28x - 14
12x^2 + 22x - 14 <===

C. f[g(x)]
3(4x - 2) + 7 =
12x - 6 + 7 =
12x + 1 <===

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Find the product -a^4(7a^5- 5a+ 5)

Nostrana [21]

$-a^4(7a^5- 5a+ 5) = - 7a^{9} +5 a^{5} -5 a^{4}$

3 0

3 years ago

the smallest angle in a triangle is one-third of the largest angle. the third angle is 10degrees more than the smallest angle. f

Alex787 [66]

A: smallest
c: largest
b: third
a+b+c=180
a=c/3
b=10+a
solve it
a=34
b=44
c=102

5 0

3 years ago

Out of students appeared in an examination 75% passed in English, 55%. passed in Mathematics, 5% failed in both subjects and 21

rusak2 [61]

Based on the percentage that passed English and those who passed Mathematics and those who failed and passed both, the total number of students who appeared in the examination are 60 students.

The number of students who passed only in Math are 12 students.

<h3>What number of students sat in the exam?</h3>

This can be found as:

= Total who passed English only + Total who passed Math only + Total who failed both + Total who passed both

Assuming the total is n, the equation becomes:

n = 0.75n - 21 + 0.55n - 21 + 21 + 0.05n

n = 1.35n - 21

21 = 0.35n

n = 21 / 0.35

= 60 students

The number who passed mathematics only is:

= (60 x 55%) - students who passed both

= 33 - 21

= 12 students

Find out more on Venn diagrams at brainly.com/question/24581814

#SPJ1

4 0

1 year ago

Use the box plots comparing the number of boy dogs and number of girl dogs attending doggy daycare each day for a month to answe

satela [25.4K]

The boxplots 1 and 2 represent the distribution of data using a five number summary for the male and the female attendance

The first box plot represents the male's boxplot.

So, we have:

Upper quartile (Q3) = 14
Lower quartile (Q1) = 2

The IQR is the difference between the above values

IQR = Q3 - Q1

So, we have:

IQR = 14 - 2 = 12

So: the IQR for the males' data is 12

<h3>(b) The difference in the median values</h3>

From the first and second boxplots, we have:

Median male = 10
Median female = 18

The difference (d) between these values is

d = 18 - 10

d = 8

So: the difference between the median values of each data set is 8

<h3>(c) The distribution of data</h3>

This is dependent on whether the dataset has an outlier or not.

From the figure, we have:

Male's data: presence of an outlier - use median
Female's data: absence of an outlier - use mean

So: the male dataset is measured by median, while the mean is a better measure of center for the female's data

<h3>(d) Reason for outliers</h3>

A possible reason for outliers is sampling problems