The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
Answer:
24
Step-by-step explanation:
Its the first model in purple. There are 6 students that represent a quarter of the class, so there is 6*4 = 24 students total.
D. 20/3 I think it’s the answe
Answer:
60 tickets for children were sold
Step-by-step explanation:
Let x be the number of sold children's tickets and let y be the number of adult tickets sold, then we can pose the following equations.
(i) Because 132 tickets were sold in total
(ii) because the total of $ obtained by sales was 931.20.
We must clear x. Then we substitute (i) in (ii)
60 tickets for children were sold
