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3 years ago

What is 965,000,000,000,000 in scientific notation

1 answer:

4 0

Scientific notation is the way that scientists easily handle very large numbers or very small numbers. For example, instead of writing 0.0000000056, we write 5.6 x 10-9.

So, if we are dealing with 965000000000000, then the answer would be:

9.65 x 10^14

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PLEASE HELP ME IF YOU CAN! please tell me how you got the answer thank you!

Law Incorporation [45]

Answer:

D) 35.6

Step-by-step explanation:

Use pythagorean theorem

22^2 + 28^2 = 1268

Take square root of 1268, which equals to 35.60898763.

8 0

2 years ago

The number 360 is increased by 25%. The result is then decreased by 50%. What is the final number?

Vladimir [108]

So if 360 is increased by 25%, you would end up with 450 (360 x 1.25), than if the result, 450 is decreased by 50% ( 450 x .50 = 225) (450 - 225 = 225) you would end up with 225.

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3 years ago

4(3x+2)=4(2x+3)+4x how many solution are their

baherus [9]

Answer:

Step-by-step explanation:

0=4 ther is just one solution

7 0

3 years ago

Read 2 more answers

The cost of a taxi ride is equal to $3.50 plus $0.25 for each mile. If a ride costs a total of $6.75 how long was the ride?

jeka57 [31]

Answer:

13 miles

Step-by-step explanation:

Write and solve an equation involving this information, using x as the distance traveled, in miles:

Cost(x) = $6.75 = $3.50 + ($0.25/mile)x

First, subtract $3.50 from both sides, obtaining: $3.25 = ($.25/mile)x.

Next, divide both sides by $0.25/mile:

$3.25

x = ------------------ = 13 miles

$0.25/mile

The length of the taxi ride was 13 miles.

7 0

2 years ago

Determine the formula for the nth term of the sequence:<br>-2,1,7,25,79,...

rodikova [14]

A plausible guess might be that the sequence is formed by a degree-4* polynomial,

$x_n = a n^4 + b n^3 + c n^2 + d n + e$

From the given known values of the sequence, we have

$\begin{cases}a+b+c+d+e = -2 \\ 16 a + 8 b + 4 c + 2 d + e = 1 \\ 81 a + 27 b + 9 c + 3 d + e = 7 \\ 256 a + 64 b + 16 c + 4 d + e = 25 \\ 625 a + 125 b + 25 c + 5 d + e = 79\end{cases}$

Solving the system yields coefficients

$a=\dfrac58, b=-\dfrac{19}4, c=\dfrac{115}8, d = -\dfrac{65}4, e=4$

so that the n-th term in the sequence might be

$\displaystyle x_n = \boxed{\frac{5 n^4}{8}-\frac{19 n^3}{4}+\frac{115 n^2}{8}-\frac{65 n}{4}+4}$

Then the next few terms in the sequence could very well be

$\{-2, 1, 7, 25, 79, 208, 466, 922, 1660, 2779, \ldots\}$

It would be much easier to confirm this had the given sequence provided just one more term...

* Why degree-4? This rests on the assumption that the higher-order forward differences of $\{x_n\}$ eventually form a constant sequence. But we only have enough information to find one term in the sequence of 4th-order differences. Denote the k-th-order forward differences of $\{x_n\}$ by $\Delta^{k}\{x_n\}$ . Then

• 1st-order differences:

$\Delta\{x_n\} = \{1-(-2), 7-1, 25-7, 79-25,\ldots\} = \{3,6,18,54,\ldots\}$

• 2nd-order differences:

$\Delta^2\{x_n\} = \{6-3,18-6,54-18,\ldots\} = \{3,12,36,\ldots\}$

• 3rd-order differences:

$\Delta^3\{x_n\} = \{12-3, 36-12,\ldots\} = \{9,24,\ldots\}$

• 4th-order differences:

$\Delta^4\{x_n\} = \{24-9,\ldots\} = \{15,\ldots\}$

From here I made the assumption that $\Delta^4\{x_n\}$ is the constant sequence {15, 15, 15, …}. This implies $\Delta^3\{x_n\}$ forms an arithmetic/linear sequence, which implies $\Delta^2\{x_n\}$ forms a quadratic sequence, and so on up $\{x_n\}$ forming a quartic sequence. Then we can use the method of undetermined coefficients to find it.

5 0

2 years ago