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Black_prince [1.1K]
3 years ago
7

Keaton bought a new Jeep for $32,000. The value of the car will depreciate at a rate of 8.5% per year. Growth or decay? What wil

l the car be worth in 5 years? When will the car be worth half of what Carson paid?
Mathematics
1 answer:
Paha777 [63]3 years ago
5 0
Part a)

Price of car is $32,000 and the value of Car is depreciating at a rate of 8.5% per year. This means the worth of car is decreasing. Hence it is a decay.

Part b)
Worth of car in 5 years.

Current Price = P = $32000
Decay rate = r = 0.085
Time = t = 5 years

Formula to be used:

A=P(1-r)^{t} \\  \\ 
A=32000(1-0.085)^{5} \\  \\ 
A=20523.69

This means, the worth of car after 5 years will be reduced to $20,523.69

Part c)
When the car will be worth half of its original amount.

Half amount = $16,000
Using the values in above formula, we get

16000=32000(1-0.085)t^{2} \\  \\ 
0.5=(0.915)^{t} \\  \\ 
t=7.8

This means, after 7.8 years the car be worth half of what Carson paid
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The pressure and volume of an expanding gas are related by the formula PV^b=C, where b and C are constants (this holds in adiaba
bazaltina [42]

The dP/dt of the adiabatic expansion is -42/11 kPa/min

<h3>How to calculate dP/dt in an adiabatic expansion?</h3>

An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression

Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min

PVᵇ = C

Taking logs of both sides gives:

ln P + b ln V = ln C

Taking partial derivatives gives:

\frac{1}{P}\frac{∂P}{∂t}  + \frac{b}{V}\frac{∂V}{∂t} = 0

Substitutituting the values b, P, V and dV/dt into the derivative above:

1/7 x dP/dt +  1.5/110 x 40 = 0

1/7 x dP/dt +  6/11 = 0

1/7 x dP/dt = - 6/11

dP/dt = - 6/11 x 7

dP/dt = -42/11 kPa/min

Therefore, the value of  dP/dt is -42/11 kPa/min

Learn more about adiabatic expansion on:

brainly.com/question/6966596

#SPJ1

4 0
1 year ago
Explain and show plz
STALIN [3.7K]

C,D and F are correct.

C is what you would think of when reading it, you walked 12 and walked 1/4(12) more.

12 + 12(1/4) =

12 + 3 =

15

D is equal to C when simplified,

12(1+1/4) =

12 + 3 =

15

F is the same as the D, it just simplified the numbers in the parenthesis

12(1+1/4) =

12(4/4 + 1/4) =

12(5/4) =

15

8 0
3 years ago
Read 2 more answers
) The density of oil in a circular oil slick on the surface of the ocean at a distance of r meters from the center of the slick
Feliz [49]

Answer:

Therefore the mass of the of the oil is 409.59 kg.

Step-by-step explanation:

Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).

The area of the disk

=The area of the outer circle - The area of the inner circle

= \pi (r+\triangle r)^2- \pi r^2

=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]

=\pi [2r\triangle r+(\triangle r)^2]

Since (Δr)² is very small, So it is ignorable.

∴A=2\pi r\triangle r

The density \delta (r)= \frac{40}{1+r^2}

We know,

Mass= Area× density

        =(2r \pi \triangle r)(\frac{40}{1+r^2}})

Total mass M=\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i

Therefore

\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i=\int_0^5 \frac{80r\pi }{1+r^2}dr

                      =40\pi[ln(1+r^2)]_0^5

                      =40\pi [ln(1+5^2)-ln(1+0^2)]

                     =40\pi ln(26)

                     = 409.59 kg (approx)

Therefore the mass of the of the oil is 409.59 kg.

3 0
3 years ago
Please help i am confused
son4ous [18]

Answer: (4)

Step-by-step explanation:

The parts listed in the congruence statements don't correspond, so they aren't necessarily congruent.

7 0
2 years ago
Factor each expression 8 16 =
dalvyx [7]
Since they are just next to each other ill take it multiplication and that would be 128 if its not let me know and ill correct it 
8 0
4 years ago
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