True or False? The circumcenter of a triangle is the center of the only circle that can be inscribed about it.

Factor this completely<br><br> P(x)=x^4-256

posledela

$\bf p(x)=x^4-256\qquad \boxed{2^8=256}\qquad p(x)=x^{2\cdot 2}-2^{4\cdot 2}
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p(x)=(x^2)^2-(2^4)^2\implies p(x)=[x^2-2^4]~[x^2+2^4]
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p(x)=[x^2-(2^2)^2]~[x^2+2^4]\implies p(x)=[(x-2^2)(x+2^2)]~[x^2+2^4]
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p(x)=(x-4)(x+4)(x^2+16)$

8 0

3 years ago

Solve the following equation by combining like terms:<br> x+x+2+3x-6= 31<br> X=

Vesnalui [34]

Answer:

X= 7

Step-by-step explanation:

x+x+2+3x-6=31 Combine x's

2x+2+3x-6=31 Continue to combine x's

5x+2-6=31 Combine whole numbers

5x-4=31 Add 4 to both sides

5x=35 Divide by 5

x=7

4 0

3 years ago

A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes

$\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}$

hence the answer is 0.4823

(iii) All are defective

$\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}$

(iv) At least one is defective

This is 1 - probability that none is defective

$\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}$

Hence the answer is 0.5177

3 0

1 year ago

A proportional relationship betweeof potatoes (x) and the price in dollars (y) is graphed, and the ordered pair (4, 3) is on the

CaHeK987 [17]

4/3 = 1/x.....4 lbs potatoes to $3 = 1 lb of potatoes to $x
cross multiply
(4)(x) = (3)(1)
4x = 3
x = 3/4
x = 0.75....so 1 lb of potatoes cost 75 cents

(8,6)...this means 8 lbs of potatoes cost $6

7 0

3 years ago

Simplify each of the following logarithmic expressions to the simplest form

AleksAgata [21]

Simplest Form: log2 (x/9)

4 0

3 years ago