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salantis [7]
3 years ago
10

Solve the following equation by combining like terms: x+x+2+3x-6= 31 X=

Mathematics
1 answer:
Vesnalui [34]3 years ago
4 0

Answer:

X= 7

Step-by-step explanation:

x+x+2+3x-6=31 Combine x's

2x+2+3x-6=31 Continue to combine x's

5x+2-6=31  Combine whole numbers

5x-4=31  Add 4 to both sides

5x=35 Divide by 5

x=7

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The production manager is going to present this information to the company's board of directors. Which graph should the manager
viktelen [127]

To best emphasize the number of defects. Manager should use graph 3 (refer the image shown):

If we talk about graph 1, it can also be used but usually we put the time line on the horizontal axis, for the convenience and the quantity to be measured on the y-axis. In the graph 1, the time is placed on the vertical axis (x-axis) so it would not be a good pick for the manager.

Same is the case with graph 2 again we have time on the vertical axis. So it is not a good idea to with graph 2.

Graph 3 could be the best to emphasize the number of defects because first of all time is placed on the horizontal axis and the quantity to be shown is on the vertical axis. Secondly, the range of the vertical axis is less so it is easy to observe the data set on the graph quite distinctively. Therefore, graph 3 is the best pick.

Graph 4 is placed correctly in terms of vertical and horizontal axes but the range of vertical axis is quite high due to which the dispersion or the display of the data is quite compressed and it gets hard to visualize.

3 0
3 years ago
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Hi! I need help with the attached question in calc. Thank you:)
Elena L [17]

Answer:

3π square units.

Step-by-step explanation:

We can use the disk method.

Since we are revolving around AB, we have a vertical axis of revolution.

So, our representative rectangle will be horizontal.

R₁ is bounded by y = 9x.

So, x = y/9.

Our radius since our axis is AB will be 1 - x or 1 - y/9.

And we are integrating from y = 0 to y = 9.

By the disk method (for a vertical axis of revolution):

\displaystyle V=\pi \int_a^b [R(y)]^2\, dy

So:

\displaystyle V=\pi\int_0^9\Big(1-\frac{y}{9}\Big)^2\, dy

Simplify:

\displaystyle V=\pi\int_0^9(1-\frac{2y}{9}+\frac{y^2}{81})\, dy

Integrate:

\displaystyle V=\pi\Big[y-\frac{1}{9}y^2+\frac{1}{243}y^3\Big|_0^9\Big]

Evaluate (I ignored the 0):

\displaystyle V=\pi[9-\frac{1}{9}(9)^2+\frac{1}{243}(9^3)]=3\pi

The volume of the solid is 3π square units.

Note:

You can do this without calculus. Notice that R₁ revolved around AB is simply a right cone with radius 1 and height 9. Then by the volume for a cone formula:

\displaystyle V=\frac{1}{3}\pi(1)^2(9)=3\pi

We acquire the exact same answer.

8 0
2 years ago
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Answer:

83%

Step-by-step explanation:

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3 years ago
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san4es73 [151]

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Step-by-step explanation:

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3 years ago
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lawyer [7]

Answer:

It has the same domain as the function f(x)=-\sqrt{-x}

Step-by-step explanation:

we have

f(x)=\sqrt{-x}

we know that

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-x\geq 0

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Multiply by -1 both sides

x\leq 0

The domain of the given function is the interval ----> (-∞,0]

All real numbers less than or equal to 0

The range of the given function is the interval ----> [0,∞)

All real numbers greater than or equal to zero

<u><em>Verify each statement</em></u>

Part 1) It has the same domain as the function f(x)=-\sqrt{-x}

<em>The statement is true</em>

The domain of the function f(x)=-\sqrt{-x} is

the interval ---> (-∞,0]

Part 2) It has the same range as the function f(x)=-\sqrt{-x}

The statement is false

The range of the function f(x)=-\sqrt{-x} is

the interval ---> (-∞,0]

Part 3) It has the same domain as the function f(x)=-\sqrt{x}

The statement is false

The domain of the function f(x)=-\sqrt{x} is

the interval ---> [0,∞)

Part 4) It has the same range as the function f(x)=-\sqrt{x}

The statement is false

The range of the function f(x)=-\sqrt{x} is

the interval ---> (-∞,0]

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3 years ago
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