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pogonyaev
3 years ago
6

What is the length of AC?

Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0
So in order to find line AC you must find line AD and DC then plus them together.

to find AD use Pythagoras theorem
a^2 = c^2 - b^2
AD^2 = 7.5^2 - 6.5^2
AD^2 = 56.25 - 42.25
AD^2 = 14
square root both sides to get rid of the ^2
AD ≈ 3.7 or 3.74

Do the same for DC
DC^2 = 10^2 - 6.5^2
DC^2 = 100 - 42.25
DC^2 = 57.75
DC ≈ 7.6

now plus AD and DC which should give u 11.3
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lara31 [8.8K]
20*31=620
620/2=310
20/2=10
31/2=15.5
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5 0
3 years ago
Read 2 more answers
What is the surface area of the right prism below ?
topjm [15]

Answer:

Step-by-step explanation:

First find the area of the 2 bases, the triangles. 6x8= 48\2= 24 + 24= 48

Now find the area of each rectangle, which there are three of them. 8x14= 112, 6x14= 84, 10x14= 140

Now add all rectangles and triangles together 48+ 112+ 84+ 140= 384

3 0
3 years ago
Find the slope of the line that goes through the points (-11, -19) & (-11, -10)
anyanavicka [17]

Answer:

<h2>The slope is undefined</h2>

Step-by-step explanation:

The slope of a line given two points can be found by using the formula

m =  \frac{ y_2 - y _ 1}{x_ 2 - x_ 1} \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are (-11, -19) & (-11, -10)

The slope is

m =  \frac{ - 10 -  - 19}{ - 11 -  - 11}  =  \frac{ - 10 + 19}{ - 11 + 11}  =  -  \frac{9}{0}  \\

Any number divided by zero is undefined so the slope of the line here is undefined.

Hope this helps you

4 0
3 years ago
Write the function that describes a parabola that has a vertex at (3,-4) and goes through the point (5,-12).
Anna007 [38]

Answer: The answer is f(x) = - 2x²+12x-22.


Step-by-step explanation:  We are given to write the function describing a parabola with vertex (3, -4)  and passing through the point (5, -12).

We know that the standard form of a parabola with vertex (h, k) is given by

f(x)-k=a(x-h)^2.

Here (h, k) = (3, -4), so we have

f(x)-(-4)=a(x-3)^2\\\\\Rightarrow f(x)+4=a(x-3)^2.~~~~~~~~~~~(I)

Also, the parabola is passing through the point (5, -12), so

-12+4=a(5-3)^2\\\\\Rightarrow -8=a\times 4\\\\\Rightarrow a=-2.

Substituting the value of 'a' above in equation (I), we have

f(x)+4=-2(x-3)^2\\\\\Rightarrow f(x)=-2(x^2-6x+9)-4\\\\\Rightarrow f(x)=-2x^2+12x-22.

Thus, the answer is f(x) = - 2x²+12x-22..

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3 years ago
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