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postnew [5]
3 years ago
11

What measures of variation indicate spread about the mean?

Mathematics
2 answers:
KIM [24]3 years ago
7 0
<span>standard deviation and variance</span>
RoseWind [281]3 years ago
5 0
Variance and Standard deviation 
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5. A square box has a volume of 64
oksano4ka [1.4K]

Answer:

a.

Step-by-step explanation:

Volume of square = length³

64 = length ³

Taking cube root in both sides

We'll get

Length = 4

Now perimeter of square = 4×L

= 4×4

= 16

5 0
2 years ago
Convert the given function into a logarithmic function: f(x)=36.77e^(-0.72x)
Likurg_2 [28]
F(x) = 36.77e^(-0.72x)
log f(x) = log36.77e^(-0.72x)
log f(x) = log 36.77 + log e^(-0.72x)
log f(x) = 3.6 + (-0.72x)log e
log f(x) = 3.6 - 0.72x
0.72x = 3.6 - log f(x)
x = 5 - 1.39 log f(x)
7 0
3 years ago
Evaluate the given integral by changing to polar coordinates... \int \int_{D}^{}} xy dA ...where D is the disk with center the o
11111nata11111 [884]

Answer:

0

Step-by-step explanation:

If we use polar coordinates, the region D can be covered by replacing (x,y) by (r*sin(Θ),rcosΘ)), with 0<r<7, 0<Θ<2π. The differential matrix

\left[\begin{array}{cc}rcos(\theta)&-rsin(\theta)\\sin(\theta)&cos(\theta)\end{array}\right]

has determinant equal to r, so we can compute the double integral as follows

\int\limits_D {xy} \, dx \, dy =  \int\limits_0^{2\pi}\int\limits_0^r r^3cos(\theta)sin(\theta) \, dr \, d\theta

(Note that we multiplied by the determinant of the Jacobian, r). A primitive for r³ is r⁴/4, thus, for Barrow's rule we have

\int\limits_0^{2\pi}\int\limits_0^r r^3cos(\theta)sin(\theta) \, dr \, d\theta = \int\limits_0^{2\pi}(\frac{r^4}{4}cos(\theta)sin(\theta)) \, |_{r = 0}^{r = 7} \, d\theta

A primitive of cos(Θ)sin(Θ) can be obtained using substitution, and it is sin²(Θ)/2 (note that the derivate of sin²(Θ) is 2sin(Θ)cos(Θ)). Therefore, taking both the dividing 4 and the 2 obtained, we have

\int\limits_0^{2\pi}(\frac{r^4}{4}cos(\theta)sin(\theta)) \, |_{r = 0}^{r = 7} \, d\theta = \frac{1}{8} \int\limits_0^{2\pi} 7^4 * \frac{cos(\theta)sin(\theta)}{2} \, d\theta = \frac{7^4}{8} (sin^2(\theta)) |_{\theta=0}^{\theta=2\pi} \\= \frac{7^4}{8} (sin^2(2\pi)-sin^2(0)) = 0

Hence, the integral is 0.

5 0
3 years ago
Jim cash the paycheck and went shopping he spent 3/8 of it on a mower 2/5 of it on at chainsaw and 180 On Tools if he has 270 le
Sever21 [200]

Declaration

Let the original amount of the paycheck be x

Equation

Paycheck - cost of mower - cost of chainsaw - 180 = 270

x - [(3/8)x + (2/5)x + 180] =  270

Solve

Change 3/8 and 2/5 to a common denominator and add.

3*5/8*5 + 2*8/5*8 = 15/40 + 16/30 = 31/40

x - [(31/40)x + 180] = 270                 Remove the outer brackets

x - (31/40)x - 180 = 270                    Evaluate the "x"s

40/40x - 31/40x - 180 = 270        

9x/40 - 180 = 270                          Add 180 to both sides

9x/40 = 180 + 270

9x/40 = 450                                  Multiply by 40

9x = 18000                                    Divide by 9

x = 18000/9

x = 2000

His paycheck was 2000 dollars.            


8 0
3 years ago
Xin graphs the equation y=4x – 6 .
Whitepunk [10]

Answer:

The slope of the line is 4

Step-by-step explanation:

Those are correct because in y = mx + b

x is always the slope and y is always the y-intercept;

So for y = 4x - 6;

4 is the slope and -6  is the y-intercept.

5 0
2 years ago
Read 2 more answers
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