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Anestetic [448]
3 years ago
14

Which situation is represented by the equation? 6n + 12 = 2n + 36

Mathematics
1 answer:
Romashka [77]3 years ago
3 0
<span>6n+12=2n+36
We move all terms to the left:
6n+12-(2n+36)=0
We get rid of parentheses
6n-2n-36+12=0
We add all the numbers together, and all the variables
4n-24=0
We move all terms containing n to the left, all other terms to the right
4n=24
n=24/4
n=6</span>
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Suppose you read online that children first count to 10 successfully when they are 32 months old, on average. You perform a hypo
creativ13 [48]

Answer:

p_v =2*P(t_{(35)}  

Step-by-step explanation:

Assuming this info from R

hist(gifted$count)

##    Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

##   21.00   28.00   31.00   30.69   34.25   39.00

## Sd

## [1] 4.314887

Data given and notation  

\bar X=30.69 represent the mean  

s=4.3149 represent the sample standard deviation

n=36 sample size  

\mu_o =32 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different than 32, the system of hypothesis would be:  

Null hypothesis:\mu = 32  

Alternative hypothesis:\mu \neq 32  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{30.69-32}{\frac{4.3149}{\sqrt{36}}}=-1.822    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=36-1=35  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(35)}  

7 0
3 years ago
In a study of the accuracy of fast food drive-through orders, McDonald’s had 33 orders that were not accurate among 362 orders o
melomori [17]

Answer:

A. We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B. Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

C. z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558  

D. z_{\alpha/2}=-1.96  z_{1-\alpha/2}=1.96

E. Fail to the reject the null hypothesis

F. So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.  

Step-by-step explanation:

Data given and notation

n=362 represent the random sample taken

X=33 represent the number of orders not accurate

\hat p=\frac{33}{363}=0.0912 estimated proportion of orders not accurate

p_o=0.10 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

A: Write the claim as a mathematical statement involving the population proportion p

We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B: State the null (H0) and alternative (H1) hypotheses

Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

C: Find the test statistic

Since we have all the info required we can replace in formula (1) like this:  

z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558  

D: Find the critical value(s)

Since is a bilateral test we have two critical values. We need to look on the normal standard distribution a quantile that accumulates 0.025 of the area on each tail. And for this case we have:

z_{\alpha/2}=-1.96  z_{1-\alpha/2}=1.96

P value

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z  

E: Would you Reject or Fail to Reject the null (H0) hypothesis.

Fail to the reject the null hypothesis

F: Write the conclusion of the test.

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.  

6 0
3 years ago
The domain of the function is given. Find the range.
xenn [34]

<em>Answer</em><em>:</em>

<em>Range</em><em>=</em><em>{</em><em> </em><em>-</em><em>5</em><em>,</em><em>-</em><em>1</em><em>,</em><em>3</em><em>,</em><em>7</em><em>)</em><em>. </em><em> </em><em> </em><em> </em><em>[</em><em> </em><em>option</em><em> </em><em>C</em><em>]</em>

<em>Please</em><em> </em><em>see</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>for</em><em> </em><em>full</em><em> </em><em>sol</em><em>ution</em><em>.</em><em>.</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em><em>.</em><em>.</em>

4 0
4 years ago
Read 2 more answers
Choose a method . Then find the product 10x15
34kurt

Answer:

150

Step-by-step explanation:

15*10

Lets get rid of the 0 for now

15*1

That is 15 added to itself 0 times so it is 15

Now lets put the 0 back

and we will get

150

5 0
3 years ago
Read 2 more answers
Can someone please help me with this, im doing a test and im stuck on this question.
Mashutka [201]

Answer:

20

Step-by-step explanation:

first do 75/50 = 1.5

then multiply red by 1.5

13 landed on red so

13 x 1.5 = 19.5

but since you round up it is 20

6 0
3 years ago
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