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Liono4ka [1.6K]
3 years ago
10

ULTICULO

Mathematics
2 answers:
yaroslaw [1]3 years ago
5 0

Answer:

12 tomato plants

Step-by-step explanation:

I hope this helped

expeople1 [14]3 years ago
5 0

Answer:768

Step-by-step explanation:

Because if You do area model then it works! You do area model like this, make a rectangle, then put your two numbers on the top and side, then do like 8x90 then that equals 720 then do 8x6 and it equals 48 then add 48 to 720 and you will get 768!

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Can someone help me with the steps to solving<br> 22-5(6v-1)=-63
faust18 [17]
22 - 5(6v - 1) = -63 First, you distribute 5 to the parentheses.

22 - 30v + 5 = -63

27 - 30v = -63

-30v = -90

v = 3
4 0
3 years ago
What fraction is geeater 2/3 or3/5
exis [7]
I find it easier with problems such as these, to turn the fractions into decimals.
2/3 = 0.666
3/5 = 0.6

which means 2/3 is greater
4 0
3 years ago
Read 2 more answers
P divided by 2 written as an algebraic expression
lina2011 [118]

Answer:

p/2

Step-by-step explanation:

Written as a fraction, p/2 is the same as p divided by 2.

5 0
3 years ago
How many miles is 1,320 feet?<br> 1/5<br> 1/4<br> 1/2<br> 2<br> none of these
hoa [83]
It's 1/4 as fraction and .25 as decimal
3 0
3 years ago
As part of the Honolulu Heart Study, a sample group of 100 individuals is selected and a study conducted to see if following a 6
adoni [48]

Answer:

t=\frac{203.8-221.4}{\frac{21.6}{\sqrt{100}}}=-8.148    

The degrees of freedom are given by:  

df=n-1=100-1=99  

and the p value would be given by:

p_v =P(t_{(99)}  

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly less than 221.4 the value of study.

Step-by-step explanation:

Information given

\bar X=203.8 represent the sample mean    

s=21.6 represent the sample standard deviation

n=100 sample size  

\mu_o =221.4 represent the value to verify

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis to test

We want to verify if the true mean is lower than 221.4, the system of hypothesis would be:  

Null hypothesis:\mu \geq 221.4  

Alternative hypothesis:\mu < 221.4  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{203.8-221.4}{\frac{21.6}{\sqrt{100}}}=-8.148    

The degrees of freedom are given by:  

df=n-1=100-1=99  

and the p value would be given by:

p_v =P(t_{(99)}  

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly less than 221.4 the value of study.

7 0
4 years ago
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