All categories

3 years ago

Find the gradient of the line segment between the points (-4,1) and (2,4). Give your answer in its simplest form.

Mathematics

2 answers:

Umnica [9.8K]3 years ago

4 0

Answer:

1/2

Step-by-step explanation:

andrew-mc [135]3 years ago

3 0

Answer:

Solution,

Let the points be A and B

A(-4 , 1)------>( X1, y1)

B(2,4)---------->( x2, y2)

Now,

Gradient:

$\frac{y2 - y1}{x2 - x1}$

$\frac{4 - 1}{2 - ( - 4)}$

$\frac{3}{2 + 4}$

$\frac{3}{6}$

$\frac{1}{2}$

Hope this helps...

Good luck on your assignment...

You might be interested in

Which expression is equivalent to 15n – 20?

Semenov [28]

The only thing you can do with this expression is to factor a 5 out of the two terms: we have

$15n-20 = 5(3n-4)$

3 0

3 years ago

Read 2 more answers

The product of two rational numbers is (-28/81). If one of them is (-2/3), the find the other.

KatRina [158]

Answer:

The other rational number is $\dfrac{14}{27}$ .

Step-by-step explanation:

First rational number is $\dfrac{-2}{3}$

Let other rational number is $\dfrac{x}{y}$

The product of two rational numbers is $\dfrac{-28}{81}$

According to question,

$\dfrac{x}{y}\times \dfrac{-2}{3}=\dfrac{-28}{81}$

Multiplying both sides by (-3/2) such that,

$\dfrac{x}{y}\times \dfrac{-2}{3}\times \dfrac{-3}{2}=\dfrac{-28}{81}\times \dfrac{-3}{2}\\\\\dfrac{x}{y}=\dfrac{14}{27}$

So, the other rational number is $\dfrac{14}{27}$ .

6 0

3 years ago

Read 2 more answers

What is the slope of the line shown in the graph? (4 points)<br> 5<br> 4<br> 1<br> 0<br> 10

Softa [21]

Answer:

There is no graph

Step-by-step explanation:

Post the graph and I can help you.

6 0

3 years ago

Simplify

Diano4ka-milaya [45]

Answer:

$\huge\boxed{\sqrt[4]{16a^{-12}}=2a^{-3}=\dfrac{2}{a^3}}$

Step-by-step explanation:

$16=2^4\\\\a^{-12}=a^{(-3)(4)}=\left(a^{-3}\right)^4\qquad\text{used}\ (a^n)^m=a^{nm}\\\\\sqrt[4]{16a^{-12}}=\bigg(16a^{-12}\bigg)^\frac{1}{4}\qquad\text{used}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\bigg(2^4(a^{-3})^4\bigg)^\frac{1}{4}\qquad\text{use}\ (ab)^n=a^nb^n\\\\=\bigg(2^4\bigg)^\frac{1}{4}\bigg[(a^{-3})^4\bigg]^\frac{1}{4}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=2^{(4)(\frac{1}{4})}(a^{-3})^{(4)(\frac{1}{4})}=2^1(a^{-3})^1=2a^{-3}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}$

$=2\left(\dfrac{1}{a^3}\right)=\dfrac{2}{a^3}$

5 0

4 years ago

The first number in the pattern is 32 the rule is to add 27

svetlana [45]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers