Question

What is the surface area of the rectangular pyramid below?

Answer 1

Answer:

$SA=41.74\ m^2$

Step-by-step explanation:

we know that

The surface area of the rectangular pyramid is equal to the area of its rectangular base plus the area of its four triangular faces

so

step 1

Find the area of its rectangular base

$A=(4.8)(3.8)$

$A=18.24\ m^2$

step 2

Find the area of its four triangular faces

$A=2[\frac{1}{2}(4.8)(2.6)]+2[\frac{1}{2}(3.8)(2.9)]$

$A=12.48+11.02=23.5\ m^2$

step 3

Find the surface area

Adds the areas

$SA=18.24+23.5$

$SA=41.74\ m^2$

Answer 2

Answer:

Step-by-step explanation:The area of the base is 24 cm2.

There are four lateral faces.

The total surface area of the figure is 66.4 cm2.

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