Answer:
The distance between A and D to the nearest tenth is;
Explanation:
Given the two points;
Applying the distance between two points formula;
![d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
substituting the given coordinates we have;
![\begin{gathered} AD=\sqrt[]{(-3-6)^2+(-2-2)^2} \\ AD=\sqrt[]{(-9)^2+(-4)^2} \\ AD=\sqrt[]{81+16} \\ AD=\sqrt[]{97} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20AD%3D%5Csqrt%5B%5D%7B%28-3-6%29%5E2%2B%28-2-2%29%5E2%7D%20%5C%5C%20AD%3D%5Csqrt%5B%5D%7B%28-9%29%5E2%2B%28-4%29%5E2%7D%20%5C%5C%20AD%3D%5Csqrt%5B%5D%7B81%2B16%7D%20%5C%5C%20AD%3D%5Csqrt%5B%5D%7B97%7D%20%5Cend%7Bgathered%7D)
Simplifying;
Therefore, the distance between A and D to the nearest tenth is;
Answer:
The probability is 2/5
Step-by-step explanation:
Here, we want to calculate the probability that the first person will sit in a yellow roller coaster car
The number of cars to select from is 6 + 9 = 15 cars
The number of yellow cars is 6
So the probability that the first person selects a yellow roller coaster car to seat is 6/15 = 2/5
We know that four snacks and three movie tickets cost $40 dollars, and when you take away 2 snacks but still keep the tickets, its $32.
2 snacks= $8
What i did to find the cost of each ticket is I divided 8 by 2 (8/2) and ended getting $4
1 snack= $4
Now to find the cost of each ticket, i divided 2 snacks ($8) and got this equation:
32 - 8= 24
3 tickets= $24
Now to find the amount for each ticket, i divided 24 by 3 (24/3) and got the answer:
1 ticket= $8
Therefore, snacks are $4 and movie tickets are $8
x tickets= 8x
x snacks= 4x
<em>Thank you! Btw can i please get brainly :3</em>
<h2>1.</h2>
Firstly, combine like terms: 
Next, subtract r on both sides of the equation: 
Next, add 8 onto both sides of the equation: 
Lastly, divide both sides by 6 and <em><u>your answer will be r = 3.</u></em>
<h2>2.</h2>
Firstly, multiply both sides by e: 
Lastly, divide both sides by 3, and <em><u>your answer will be 
</u></em>
