To solve this equation there are many ways you can do to solve. One way is to simply substitute one variable for another.
5x = 5y - 25
X = y - 5
10y = 42 + 2x
10y = 42 + 2(y - 5)
10 y = 42 + 2y - 10
8y = 32
Y = 4.
X = y - 5
X = 4 - 5
X = -1.
P(X,y) = P(-1,4). This would be the solution or the point where they would intersect.
3 - 2.5 = 0.5
shanay rode 1/2 a mile more
hope this helps :)
Answer:
try asking a master, ok?
Step-by-step explanation:
Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.