3 years ago

EFGH is a parallelogram. Find the measure of FG.

Mathematics

1 answer:

Elan Coil [88]3 years ago

4 0

Answer:

FG = 47

Step-by-step explanation:

The opposite sides of a parallelogram are parallel and congruent, thus

EH = FG, that is

5z - 18 = 3z + 8 ( subtract 3z from both sides )

2z - 18 = 8 ( add 18 to both sides )

2z = 26 ( divide both sides by 2 )

z = 13

Hence

FG = 3z + 8 = (3 × 13) + 8 = 39 + 8 = 47

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A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectil

Furkat [3]

Answer:

t = 5.25 seconds

Step-by-step explanation:

Given that,

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation:

$h(t)=-16t^2+48t+190$

It is assumed to find the time when the projectile will hit the ground. When the projectile hit the ground, its height is equal to 0 such that,

$-16t^2+48t+190=0$

It forms a quadratic equation such that,

$t=\dfrac{-b+\sqrt{b^{2}-4ac } }{2a},\dfrac{-b-\sqrt{b^{2}-4ac } }{2a}\\\\t=\dfrac{-48+\sqrt{(48)^{2}-4\times (-16)(190) } }{2\times (-16)},\dfrac{-48-\sqrt{(48)^{2}-4\times (-16)(190) } }{2\times (-16)}\\\\t=-2.25, 5.25$