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2 years ago

Can someone please help me

1 answer:

6 0

Given the function, P = 22x - 1200, be the model determining the profit of Henry's new business. Now, the lowest amount that P could generate would be when Henry does not sell any shirt. This gives x a value of 0 and P = 0 - 1200 = -1200.

Now, he can get the highest profit when he gets to sell all of the 600 shirts. Thus, we have x = 600 and P = 22(600) - 1200 = 12000.

Since the minimum and maximum values of P are -1200 and 12000, then the range of P would be {-1200 ≤ p ≤ 12000}.

Answer: D) {-1200 ≤ p ≤ 12000}

Read more on Brainly.com - brainly.com/question/3939189#readmore

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Step-by-step explanation:

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3 years ago

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Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

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$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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hodyreva [135]

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2 years ago

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