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Dima020 [189]
3 years ago
5

A car factory produces 100 cars in a day. If c is the total number of cars produced in d days, which equation represents the num

ber of cars as a function of the number of days?
Mathematics
2 answers:
aliya0001 [1]3 years ago
7 0
C=100d

c is the total, d is the factor
c is dependent variable, d independant
Yakvenalex [24]3 years ago
4 0

Answer:

<em>The equation that represents the number of cars as a function of the number of days will be:  c=100d</em>

Step-by-step explanation:

The factory produces 100 cars in a day.

<em>For getting the total number of cars, we need to multiply 100 with the total number of days.</em>

So, the total number of cars produced in d days =100*d= 100d

Given that, the total number of cars produced in d days is c.

So, the equation that represents the number of cars as a function of the number of days will be:  c=100d

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xxTIMURxx [149]

Answer:

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

p_v =2*P(t_{(1699)}>1.971)=0.049  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation  

\bar X=669 represent the sample mean

s=732 represent the sample standard deviation

n=1700 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0. represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:  

Null hypothesis:\mu = 634  

Alternative hypothesis:\mu \neq 634  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(1699)}>1.971)=0.049  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

3 0
3 years ago
What us the ratio of 8 pennies and 20 dimes
inysia [295]
The ratio would be 8:20 or 8 to 20
7 0
3 years ago
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Write three numbers grater than 20 that have 9 as a factor
Burka [1]
27, 36, 45 are greater than 20 and multiples of 9.
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3 years ago
(04.02 MC)<br> Solve the system of equations.<br> 5x + y = 9<br> 3x + 2y = 4
goblinko [34]

Answer:

(2,-1)

Step-by-step explanation:

Multiply first equation by 2:

10x + 2y = 18

Subtract the second equation from this so that the 2y terms cancel:

10x - 3x = 18 - 4

7x = 14

x = 2

Plug into first equation to find y:

5(2) + y = 9

10 + y = 9

y = -1

The answer is (2,-1)

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3 years ago
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Please im desperate please help me
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