Equation in point slope form of a line:
y-y₀=m(x-x₀)
m=slope
(x₀,y₀)=(-4,7)
m=2/3
y-7=(2/3)(x+4)
Answer: y-7=(2/3)(x+4)
By letting

we get derivatives


a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

Examine the lowest degree term
, which gives rise to the indicial equation,

with roots at r = 0 and r = 4/5.
b) The recurrence for the coefficients
is

so that with r = 4/5, the coefficients are governed by

c) Starting with
, we find


so that the first three terms of the solution are

Use this equation to solve the problem:
x - (x * .25) = 40
This equation is saying the original price times itself by 25% is 40.
x - (x * .25) = 40
Simplify.
x - .25x = 40
.75x = 40
Divide both sides by .75.
x = 53.33
The original price was $53.33
Answer:
x = ± 2
Step-by-step explanation:
Given
3x² = 12 ( divide both sides by 3 )
x² = 4 ( take the square root of both sides )
x = ±
= ± 2