Answer:
rawrrrrrr mannnnnn
Step-by-step explanation:
The slope intercept form is y = -x - 4
To find the slope intercept form given a couple of points, start by finding the slope using the slope equation.
m(slope) = (y2 - y1)/(x2 - x1)
m = (-5 - 0)/(1 - -4)
m = -5/5
m = -1
Now we look for the intercept using slope intercept form, our slope and a point.
y = mx + b
0 = -4(-1) + b
0 = 4 + b
-4 = b
Now we can use those two things top model the equation.
y = -x - 4
Step-by-step explanation:
<h2>
<em><u>concept :</u></em></h2><h2 /><h2>
<em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.</u></em></h2><h2 /><h2>
<em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.</u></em></h2><h2 /><h2>
<em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:</u></em></h2><h2 /><h2>
<em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:Given equations of lines are</u></em></h2><h2 /><h2>
<em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:Given equations of lines are4y = 5x-10</u></em></h2><h2 /><h2>
<em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:Given equations of lines are4y = 5x-10or, y = (5/4)x(5/2).</u></em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>(</em><em>1</em><em>)</em></h2><h2 /><h2>
<em><u>5y + 4x = 35</u></em></h2><h2 /><h2>
<em><u>5y + 4x = 35ory = (-4/5)x + 7.</u></em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>(</em><em>2</em><em>)</em></h2><h2 /><h2>
<em><u>Let m and n be the slope of equations i and ii, respectively.</u></em></h2><h2 /><h2>
<em><u>Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4</u></em></h2><h2 /><h2>
<em><u>Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4n= -4/5</u></em></h2><h2 /><h2>
<em><u>Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4n= -4/5therefore, mx n = -1</u></em></h2><h2 /><h2>
<em><u>Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4n= -4/5therefore, mx n = -1Hence, the lines are perpendicular.</u></em></h2>
The equation
is plotted on graph below (red line)
Translating
three units to the left can be done by choosing any coordinates on
.
Let choose (0,0) and (2,1)
Translating 3 units on to the left gives the new coordinates (0-3, 0)=(-3,0) and (2-3, 1)=(-1, 1)
The gradient of the two functions will stay the same since the lines are parallel to each other, so m = 0.5
By joining the two coordinates (-3,0) and (-1,1), we see that the translated line crosses y-axis at 1.5
The equation of translated line is given
use the distance formula
You ll need to do it t times:
x1 y1 x2 y2
(-1, 5) (4, 2) = (-1, 5) (4, 2)
(4, 2) (0,0)
(0,0) (5,5)
(5,5) (-1, 5)
then add all your results
