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lesya [120]
4 years ago
15

What is the value of x in the equation 0.2(x + 1) + 0.5x = –0.3(x – 4)?

Mathematics
2 answers:
Kisachek [45]4 years ago
8 0
I hope this helps you



0,2x+0,2+0,5x= -0,3x+1,2


0,7x+0,3x=1,2-0,2


x=1
valkas [14]4 years ago
8 0

Answer:

The value of the x is 1 .

Step-by-step explanation:

As given the expression in the question.

0.2(x + 1) + 0.5x = –0.3(x – 4)

Now first open the bracket

0.2x + 0.2 + 0.5x = –0.3x – 4 × -0.3

0.2x + 0.2 + 0.5x = –0.3x + 1.2

0.2x + 0.5x + 0.3x =  1.2 - 0.2

1.0x =  1.0

x = \frac{1.0}{1.0}

x = 1

Therefore the value of the x is 1 .

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Natalija [7]
Answer: It took 18 Months for Michelle to collect 59 dolls.


Explanation:
First, let’s right an equation for this. Michelle started with 5 dolls in a bar collection (I have no clue what that is but i’ll roll with it), and each month she bought 3 more, so 5 dolls plus the 3 dolls per month equals 59 at some point.

5 dolls + 3 dolls per month = 59 dolls
OR
5 + 3m = 59

The point of this question is to find how many months (m) it took in order to get to 59 dolls and there’s multiple ways you can do this:

1) just plug in random numbers into m to see how long it takes to get to 59 [this option might take a while]

2) Try to isolate m (get every number out of the equation) to find out the value of m. [I’m most familiar with this way]

First, subtract 5 from 5 in the equation in order to get rid of it, since we’re trying to get all whole numbers out of the equation and only have m left. You subtract 5 from 59 since the equal sign is kind of like a mirrror, whatever you do to one side you have to do to the other. So, 5-5 is 0, and 59- is 54.

Now you’re left with 3m=54. In order to isolate the m, divide 3 by 3 to get rid of the 3, then divide 54 by 3, which is 18.

In order to check your work, plug 18 into m just to see if it works or not:

5+3m=59 —-> 5+ 3(18)= 59

3 times 18 is 54, plus 5 is 59. So, Mi hells took 18 months to collect her 59 dolls. Hope this helped!
3 0
3 years ago
Eliminate the parameter. x = t2 + 1, y = t2 - 1
Alexus [3.1K]
\bf \begin{cases}
x=t^2+1\implies x-1=\boxed{t^2}\\
y=t^2-1\\
----------\\
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Answer:

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