Answer: its geometric
Step-by-step explanation: The numbers are separated and are counting up Individually
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Answers:</h3>
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Work Shown:
Part 1
Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.
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Part 2
In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2
In this case, a = sqrt(x-1) and b = 5.
You could also use the box method as a visual way to expand out 
Answer:
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
x = - 6
Replace the range for f(x)
So...
0=4-2x
x=2
4=4-2x
x=0
8=4-2x
x=-2
Solve!
These are your domains!
The graphed polynomial seems to have a degree of 2, so the degree can be 4 and not 5.
<h3>
Could the graphed function have a degree 4?</h3>
For a polynomial of degree N, we have (N - 1) changes of curvature.
This means that a quadratic function (degree 2) has only one change (like in the graph).
Then for a cubic function (degree 3) there are two, and so on.
So. a polynomial of degree 4 should have 3 changes. Naturally, if the coefficients of the powers 4 and 3 are really small, the function will behave like a quadratic for smaller values of x, but for larger values of x the terms of higher power will affect more, while here we only see that as x grows, the arms of the graph only go upwards (we don't know what happens after).
Then we can write:
y = a*x^4 + c*x^2 + d
That is a polynomial of degree 4, but if we choose x^2 = u
y = a*u^2 + c*u + d
So it is equivalent to a quadratic polynomial.
Then the graph can represent a function of degree 4 (but not 5, as we can't perform the same trick with an odd power).
If you want to learn more about polynomials:
brainly.com/question/4142886
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