2 years ago

Help please and fast!

Mathematics

2 answers:

Brilliant_brown [7]2 years ago

6 0

= [3x3^-2x(-2)^6/2x3^-1x(-2)^5]^2 = 1

Veseljchak [2.6K]2 years ago

6 0

Answer:

Step-by-step explanation:

$[\frac{3a^{-2} b^6}{2a^{-1}b^5}] ^{2} \\=[1.5 a^{-2-(-1)} b^{6-5}]^2\\=[1.5a^{-2+1}b]^2\\=[1.5a^{-1}b]^2\\\\Substituting\ a=3,b=-2, we\ get,\\=[1.5*3^{-1}*-2]^2\\=[1.5*1/3*-2]^2\\=[1/2*-2]^2\\=[-1]^2\\=1$

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