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coldgirl [10]
4 years ago
6

Where can the execute disable bit (edb) technology be disabled?

Computers and Technology
1 answer:
ladessa [460]4 years ago
5 0
You can probably disable it from your BIOS, it might also be listed as “Trusted Execution Platform”.
You might be interested in
Write a while loop that prints
Nana76 [90]

Answer:

The program to this question as follows:

Program:

#include <iostream> //defining header file

using namespace std;

int main() //defining main method

{

int squ=0,n=0; //defining variable

cout<<"Square between 0 to 100 :"; //message

while(n<100) //loop for calculate Square

{

n=squ*squ; //holing value in n variable

cout<<n<<" "; //print Square

squ++; //increment value by 1

}

cout<<endl; //for new line

n=1; //change the value of n

cout<<"Positive number, which is divisible by 10: "; //message

while (n< 100) //loop for check condition

{

if(n%10==0) //check value is divisible by 10

{

cout<<n<<" ";//print value

}

n++; //increment value of n by 1

}

cout<<endl; //for new line

cout<<"Powers of two less than n: "; //message

n=1; //holing value in n

while (n< 100) //loop for check condition

{

cout<<n<<" ";//print value

n=n*2; //calculate value

}

return 0;

}

Output:

Square between 0 to 100 :0 1 4 9 16 25 36 49 64 81 100  

Positive number, which is divisible by 10: 10 20 30 40 50 60 70 80 90  

Powers of two less than n: 1 2 4 8 16 32 64  

Explanation:

In the above program, two integer variable "squ and n" is defined, then three while loop is declared, which is used to calculate different values, that can be described as follows:

  • In the first while loop both "n and squ" variable is used, in which n is used for check range and "squ" is used to calculate the square between 1 to 100.
  • The second, while it is used to calculate the positive number, which is divisible by 10, in this only n variable is used, that calculates the value and check its range.
  • Then the last while loop is used which is used to calculate the double of the number, which is between 1 to 100 range.  
6 0
4 years ago
______ norms are usually unstated rules that regulate members' interaction.
andrey2020 [161]
Hey there! Hello!

The answer to this problem is most likely group norms. The definition given above pretty much explains it: they're an unspoken/unwritten set of informal rules that dictate a group member's actions.
 
They allow for people to know how to act in social situations while also knowing who is acting out of place according to the group norms. It's a bit difficult to understand exactly what they are, since they are unstated and all. 

Hope this helped you out! Feel free to ask me any additional questions if you have any. 

–Lamb :-)
4 0
3 years ago
Green computing can be achieved by: a. using video conferencing, electronic meeting systems, and groupware. b. replacing meeting
Rama09 [41]

Answer: using video conferencing, electronic meeting systems, and groupware

Explanation:

Green computing simply means the use of computer in a way that's environmental friendly.

One way to achieve this is through using video conferencing, electronic meeting systems, and groupware. This allows the use of computers not to have a negative effect on the environment.

4 0
3 years ago
Complete the printtictactoe function with char parameters horizchar and vertchar that prints a tic-tac-toe board with the charac
lora16 [44]
Void printtictactoe(char horizchar, char vertchar)
{
int i,j;
int scale = 5;

for(j=0; j<3; j++) {
   for (i = 0; i < scale; i++)
      printf("%*c%*c\n", scale+1, vertchar, scale+1, vertchar);
      if (j < 2) 
         for (i = 0; i < (scale * 3)+2; i++)
             printf("%c", horizchar);
             printf("\n");
    }
}

I left out many braces because of the layout issues with this website. There is a scale factor you can set to the desired size of the board cells!
3 0
3 years ago
The ticketing system at the airport is broken, and passengers have lined up to board the plane in the incorrect order. This line
wolverine [178]

Answer:

See explaination

Explanation:

The program code

import java.util.ArrayList;

public class Main

{

public static void main(String[] args)

{

ArrayList<AirlineTicket> tickets = new ArrayList<AirlineTicket>();

//This creates a randomized list of passengers

addPassengers(tickets);

for(AirlineTicket elem: tickets)

{

System.out.println(elem);

}

//This creates a TicketOrganizer object

TicketOrganizer ticketOrganizer = new TicketOrganizer(tickets);

//These are the methods of the ticketOrganizer in action

System.out.println("\nPassengers Ordered by Boarding Group:");

ticketOrganizer.printPassengersByBoardingGroup();

System.out.println("\nPassengers in line who can board together:");

ticketOrganizer.canBoardTogether();

}

//Do not touch this method! It is adding random passengers to the AirlineTicket array

public static void addPassengers(ArrayList<AirlineTicket> tickets)

{

String[] seats = {"A","B","C","D","E","F"};

for(int index = 0; index< 15; index++)

{

int random = (int)(Math.random() * 5);

AirlineTicket ticket = new AirlineTicket("Passenger " + (index+1), seats[random], ((int)(Math.random()*5)+1), ((int)(Math.random()*8)+1));

tickets.add(ticket);

}

}

}

class TicketOrganizer

{

private ArrayList<AirlineTicket> tickets ;

//constructor with parameter as an arraylist of AirlineTicket

public TicketOrganizer(ArrayList<AirlineTicket> tickets)

{

this.tickets = tickets;

}

//methhods to return the arraylist of airlines

public ArrayList<AirlineTicket> getTickets()

{ //re-organize the ticket first

ArrayList<AirlineTicket> tickets_organized = new ArrayList<AirlineTicket>();

for(int i=1; i<=5; i++)

{

for(AirlineTicket ticket: tickets)

{

if(ticket.getBoardingGroup() == i)

{

tickets_organized.add(ticket);

}

}

}

return tickets_organized;

}

//print the tickets based on boardingGroup

public void printPassengersByBoardingGroup()

{

int count = 0;

for(int i=1; i<=5; i++)

{

System.out.println("Boarding Group " + i + ":");

for(AirlineTicket ticket : tickets)

{

if(ticket.getBoardingGroup() == i)

{

System.out.println("Passenger " + ticket.getName());

}

}

}

See attachment for sample output

4 0
4 years ago
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