Answer:
By Using the Greedy- Activity- Selection algorithm
Explanation:
The Greedy- Activity- Selection algorithm in this case involves
First finding a maximum size set S1, of compatible activities from S for the first lecture hall.
Then using it again to find a maximum size set S2 of compatible activities from S - S1 for the second hall.
This is repeated till all the activities are assigned.
It requires θ(n2) time in its worse .
Answer:
Income requirement is met.
Explanation:
(minIncome > income) will evaluate to false
(cutOff < income) will evaluate to false
the else portion will be executed which is "Income requirement is met"
Answer:
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Explanation:
Answer:
I think the answer would be 60x something but I'm not for sure