3 years ago

How many real solutions does the equation 8x^2 − 10x + 15 = 0 have?

Mathematics

2 answers:

Leto [7]3 years ago

6 0

Answer:

It has no real solutions.

Step-by-step explanation

Once you calculate the discriminant, D= (-10)^2 -4 (8)(15), you simplify the expression to get D= -380, which has no real solutions.

Svet_ta [14]3 years ago

4 0

Answer:

No solutions

Step-by-step explanation:

Quadratic equations are in the form of ax^2+bx+c, so a = 8, b= -10, and c = 15.

Use b^2 - 4ac to find the discriminant.

-10^2 - 4(8)(15) = <em>-580</em>

If a discriminant is < 0 then there are no real solutions to a quadratic equation. -580 < 0

Therefore, there are no real solutions

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