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3 years ago

9

PLEASE HELP ASAP! :(

1 answer:

Law Incorporation [45]3 years ago

4 0

I’ll help but u where is the question

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FACTORED POLYNOMIAL ONLY

Leto [7]

Answer: $5x^{3}$ ( $x^{3}$ +2x+3)

3 0

3 years ago

Help!!! Which one no need to explain!

azamat

Answer: A add the equations and C: Subtract the bottom equation from the top equation.

Step-by-step explanation: By adding the equations, you are left with

12x=8 which successfully eliminates the y values and subracting the bottom equation from the top equation.

Hope this helps! :)

5 0

3 years ago

Please help will mark brainiest

guapka [62]

Answer:

I think it is B, AB or CD and AB || CD

Step-by-step explanation:

8 0

2 years ago

Drag the tiles to list the sides of △MNO from shortest to longest.

sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

MO/Shortest MO/Medium and MO/Longest

a) <u>Friday</u>

b) <u>70 minutes</u>

c) <u>40%</u>

d) Yes<u>,</u> <u>the sum of the </u><u>mean</u><u> number of </u><u>minutes spent</u><u> on </u><u>aerobic</u><u> training and the mean number of minutes spent on </u><u>strength</u><u> training is equal to the mean </u><u>total</u><u> number of minutes spent </u><u>training.</u>

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= $\frac{}{MO}$

The next shortest side is the side opposite ∠M(61°) = $\frac{}{NO}$

The longest side is the side opposite ∠O(65°) = $\frac{}{MN}$

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on <u>Friday</u>

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = <u>70 minutes</u>

<u />

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

$The$ $percentage$ $spent$ $on$ $strength$ $training$ = $\frac{120}{300}$ × $100 =$ $\frac{40}$ %

d) The mean number of minutes spent on strength training is found as follows;

$Mean_{strength} =\frac{120}{5} =24$

The mean number of minutes spent on aerobic training is found as follows;

$Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36$

$Mean_{strength} +Mean_{aerobic} =24+36=60$

The mean total number of minutes spent training, $Mean_{total}$ = $\frac{300}{5}$ = 60

Therefore;

$Mean_{strength}+Mean_{aerobic} = Mean_{total} \\$

Learn more here:

brainly.com/question/2962546

4 0

2 years ago

Determine the domain of the function h=9x/x(x^2-49)

Juliette [100K]

ANSWER

$( - \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , + \infty )$

EXPLANATION

The given function is

$h(x) = \frac{9x}{x( {x}^{2} - 49) }$

This function is defined for values where the denominator is not equal to zero.

$x( {x}^{2} - 49) \ne0$

$x(x - 7)(x + 7) = 0$

The domain is

$x \ne - 7, x \ne0, \: and \: x \ne 7,$

Or

$( - \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , + \infty )$

8 0

2 years ago