Step-by-step explanation:
each department has 3 options for their representative.
and each of these options can be associated with the 3 options of the next department. and so on.
so, we have
3×3×3×3 = 3⁴ = 81
possibilities to firm that committee overall.
You need to find "two-fifths of 30." Of here means multiplication:
![\begin{aligned}\dfrac{2}{5}\cdot 30 &= \dfrac{2}{5}\cdot\dfrac{30}{1}\\[0.5em] &= \dfrac{60}{5}\\[0.5em] &= 12\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cdfrac%7B2%7D%7B5%7D%5Ccdot%2030%20%26%3D%20%5Cdfrac%7B2%7D%7B5%7D%5Ccdot%5Cdfrac%7B30%7D%7B1%7D%5C%5C%5B0.5em%5D%20%26%3D%20%5Cdfrac%7B60%7D%7B5%7D%5C%5C%5B0.5em%5D%20%26%3D%2012%5Cend%7Baligned%7D)
There are 12 athletes in the club.
Answer:
Area of the new rectangle = 148.8 cm square
Step-by-step explanation:
Let x be the dimensions of the rectangle then the
Perimeter of the Original rectangle= 2(L+B)
= 2 ( 3x+2x) = 2(5x)= 10xcm
If the length is increased by eight the new length would be 3x+ 8
and width would be 2x+x= 3x after 50 % increase
Perimeter of the new rectangle= 2(L+B)
= 2 ( 3x+8 +3x)
= 2 (6x+8)
= 12x + 16
Ratio of the new perimeter to the original perimeter is
New perimeter : Original perimeter
8 : 5
12x+ 16 : 10x cm
80x= 60x + 16
20x= 16
x= 16/20= 4/5
Putting the value of length and breadth in place of x
Area of the new rectangle = L*B = 3 * (4/5) +8 *3(4/5)=
= 12+ 40/5 * 12/5
= 62/5* 12/5
= 744/5
= 148.8 cm square
