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mars1129 [50]
4 years ago
6

tim and his brother are building towers out of blocks. Tim is using blue blocks that are 6 cm tall and his brother is using gree

n blocks that are 8 cm tall. They both made towers the same height. What is the shortest possible height of the tower? how many of each color block did they use
Mathematics
1 answer:
Karolina [17]4 years ago
7 0

The shortest possible height of tower is 24 cm.

Tim used 4 blue blocks and his brother used 3 green blocks.

Step-by-step explanation:

Given,

Height of blue block = 6 cm

Height of green block = 8 cm

We will take least common multiple to find the shortest possible height.

6 = 2*3

8 = 2*2*2

LCM = 2*2*2*3 = 24 cm

The shortest possible height of tower is 24 cm.

Number of blue blocks used = \frac{24}{6} = 4

Number of green blocks used = \frac{24}{8} = 3

Tim used 4 blue blocks and his brother used 3 green blocks.

Keywords: LCM, multiplication

Learn more about multiplication at:

  • brainly.com/question/11203617
  • brainly.com/question/11253316

#LearnwithBrainly

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MA_775_DIABLO [31]

Answer:

<h2>$21000</h2>

Step-by-step explanation:

This problem is on simple interest calcultion

A=P(1+r*n)

 where

A=accumulated amount (final)

P= principal amount (initial), $15,000

r=interest written as decimal, 8% = 8/100= 0.08

n=number of years, 5years

Substituting into the expression we have

A=15000(1+0.08*5)

A= 15000(1+0.4)

A=15000(1.4)

A=$21000

<h2>Hence the ending balance that lucy would pay is $21000</h2>
5 0
3 years ago
In 2008, the price of gasoline was $2.79 per gallon. In 2009, the price of gasoline was
ikadub [295]

Answer:

36%

Step-by-step explanation:

line up $ and % data like this:

$2.79 represents 100%

$3.79 represents  X%

cross multiply

X*2.79 = 3.79*100

divide both sides by 2.79

X= 3.79*100 / 2.79 ≈ 136%

so it increased 36%

7 0
3 years ago
What is the answer to -5 ( 4w +12) =15 make sure you write the answer as a decimal
seropon [69]

Answer:

w= -3.75

Step-by-step explanation:

-5(4w+12) =15

-20w -60=15

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w=-3.75

8 0
4 years ago
Read 2 more answers
Rationalise the denominator of:<br>1/(√3 + √5 - √2)​
Paul [167]

Step-by-step explanation:

\large\underline{\sf{Solution-}}

Given expression is

\rm :\longmapsto\:\dfrac{1}{ \sqrt{3}  +  \sqrt{5}  -  \sqrt{2} }

can be re-arranged as

\rm :\longmapsto\:\dfrac{1}{ \sqrt{3}   -   \sqrt{2}   +  \sqrt{5} }

\rm \:  =  \: \dfrac{1}{( \sqrt{3}  -  \sqrt{2} ) +  \sqrt{5} }

On rationalizing the denominator, we get

\rm \:  =  \: \dfrac{1}{( \sqrt{3}  -  \sqrt{2} ) +  \sqrt{5} }  \times \dfrac{( \sqrt{3}  -  \sqrt{2} ) -  \sqrt{5} }{( \sqrt{3}  -  \sqrt{2} ) -  \sqrt{5} }

We know,

\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) =  {x}^{2} -  {y}^{2} \: }}

So, using this, we get

\rm \:  =  \: \dfrac{ \sqrt{3} -  \sqrt{2}   -  \sqrt{5} }{ {( \sqrt{3}  -  \sqrt{2} )}^{2}  -  {( \sqrt{5}) }^{2} }

\rm \:  =  \: \dfrac{ \sqrt{3} -  \sqrt{2}   -  \sqrt{5} }{3 + 2 - 2 \sqrt{6}   - 5}

\rm \:  =  \: \dfrac{ \sqrt{3} -  \sqrt{2}   -  \sqrt{5} }{5 - 2 \sqrt{6}   - 5}

\rm \:  =  \: \dfrac{ \sqrt{3} -  \sqrt{2}   -  \sqrt{5} }{ - 2 \sqrt{6}}

\rm \:  =  \: \dfrac{ - ( -  \sqrt{3} +  \sqrt{2}  + \sqrt{5}) }{ - 2 \sqrt{6}}

\rm \:  =  \: \dfrac{-  \sqrt{3} +  \sqrt{2}  + \sqrt{5}}{2 \sqrt{6}}

On rationalizing the denominator, we get

\rm \:  =  \: \dfrac{-  \sqrt{3} +  \sqrt{2}  + \sqrt{5}}{2 \sqrt{6}}  \times \dfrac{ \sqrt{6} }{ \sqrt{6} }

\rm \:  =  \: \dfrac{-  \sqrt{18} +  \sqrt{12}  + \sqrt{30}}{2  \times 6}

\rm \:  =  \: \dfrac{-  \sqrt{3 \times 3 \times 2} +  \sqrt{2 \times 2 \times 3}  + \sqrt{30}}{12}

\rm \:  =  \: \dfrac{-  3\sqrt{2} + 2 \sqrt{3}   + \sqrt{30}}{12}

Hence,

\boxed{\tt{ \rm \dfrac{1}{ \sqrt{3}  +  \sqrt{5}  -  \sqrt{2} } =\dfrac{-  \sqrt{3 \times 3 \times 2} +  \sqrt{2 \times 2 \times 3}  + \sqrt{30}}{12}}}

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

<h3><u>More Identities to </u><u>know:</u></h3>

\purple{\boxed{\tt{  {(x  -  y)}^{2} =  {x}^{2} - 2xy +  {y}^{2}}}}

\purple{\boxed{\tt{  {(x   +   y)}^{2} =  {x}^{2} + 2xy +  {y}^{2}}}}

\purple{\boxed{\tt{  {(x   +   y)}^{3} =  {x}^{3} + 3xy(x + y) +  {y}^{3}}}}

\purple{\boxed{\tt{  {(x - y)}^{3} =  {x}^{3} - 3xy(x  -  y) -  {y}^{3}}}}

\pink{\boxed{\tt{  {(x + y)}^{2} +  {(x - y)}^{2} = 2( {x}^{2} +  {y}^{2})}}}

\pink{\boxed{\tt{  {(x + y)}^{2}  -  {(x - y)}^{2} = 4xy}}}

6 0
3 years ago
Which expressions are equivalent to the one below? Check all that apply. 21^x/3^x
satela [25.4K]

Answer:

<em>options:  A,C,E </em>are correct.

Step-by-step explanation:

We have to find the expression equivalent to the expression:

\dfrac{21^x}{3^x}

we know that: 21^x=(3\times7)^x\\\\21^x=3^x\times7^x

Hence,

\dfrac{21^x}{3^x}=\dfrac{3^x\times7^x}{3^x}=7^x-----(1)

A)   (\dfrac{21}{3})^x= 7^x  (same as(1))

Hence, option A is correct.

B)  7 ; which is a different expression from (1)

Option B is incorrect.

C) 7^x   (Same as (1))

Option C is correct.

D) (21-3)^x=18^x   which is a different expression from (1)

Hence, option D is incorrect.

E) \dfrac{7^x\times3^x}{3^x}=7^x   ; which is same as (1)

Hence, Option E is correct.

F) 3^x  ; which is not same as expression (1)

Hence, option F is incorrect.

5 0
4 years ago
Read 2 more answers
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