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4 years ago

Percentage of the different pet people own:

Mathematics

1 answer:

Verizon [17]4 years ago

8 0

Answer:

The answer should be 120.

Step-by-step explanation:

30% of 400 = 120 cats

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867 m as a fraction ....

lesantik [10]

Answer:

867000 / 1000

Step-by-step explanation:

To express in the form of a fraction :

An expression could be said to be in fraction form, if written in the form ; a/b ; where a = numerator and b = denominator

Hence the number :

867 m could be expressed as a fraction :

867 / 1 where 867 = numerator ; 1 = denominator

867000 / 1000 ; 867000 = numerator ; 1000 = denominator

3 0

3 years ago

If Jenny gets a bonus of $50 one week, and works h hours that week, write an expression for the total amount of money she would

Sergeeva-Olga [200]

$50+h(how much she makes per hour)
So if she makes $10 per hour, the expression would be $50+$10h.
The answer would be 10h+50 if she makes 10 dollars per hour.

3 0

3 years ago

Plz guys I need help

k0ka [10]

the answer will be 16x

1 gallon 16x as constant variable

6 0

3 years ago

Evaluate the following: 42 ÷ (3 + 1).

shusha [124]

The sum of y and 7 is y+7
42 divided by (3+1) simplifies to 42 divided by 4 which equals 10.5

3 0

3 years ago

Read 2 more answers

An inventor has developed a new, energy-efficient lawn mower engine. He claims that the engine will run continuously for 5 hours

Anarel [89]

Answer:

a) The null and alternative hypothesis are:

$H_0: \mu\geq 300\\\\H_1: \mu$

b) test statistic t=-5.59 (df=499).

c) P-value=0

d) Reject the null hypothesis. The sample is enough evidence to reject the inventor's claim and to conclude that the run time is lower than 300 minutes.

Step-by-step explanation:

We have to perform an hypothesis test on the mean, with estimated standard deviation. We want to test the claim that the run time differs from 300 minutes.

The null and alternative hypothesis are:

$H_0: \mu\geq 300\\\\H_1: \mu$

The level of significance is 0.05.

The test statistic t is

$t=\frac{M-\mu}{s/\sqrt{N}} =\frac{295-300}{20/\sqrt{500}} =\frac{-5}{0.894} =-5.59$

The degrees of freedom are

$df=n-1=500-1=499$

The P-value for this t=-5.59, with 499 degrees of freedom is P=0. The null hypothesis is rejected.

The sample result is enough evidence to reject the inventor's claim, specially because the large sample size.

6 0

3 years ago