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kondor19780726 [428]
3 years ago
11

Six rectangles each with a common base width of 22 have lengths of 1,4,9,16,251,4,9,16,25, and 3636. What is the sum of the area

s of the six rectangles?
Mathematics
1 answer:
vazorg [7]3 years ago
5 0
22(1)+22(4)+22(9)+22(16)+22(251)+22(4)+22(9)+22(16)+22(25)+22(3636)
but you can do this easier
22(1+4+9+16+251+4+16+25+3636)
it will give you the same number
so the answer is 87,362
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mihalych1998 [28]

Answer:

Step-by-step explanation:

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Answer:

\approx \frac{73}{12}\left(1 - \frac{1} {2\cdot73^2}\right)

Step-by-step explanation:

= \sqrt{\frac{73^2-1) 1}{12^2}} \\

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= \sqrt{\frac{73^2}{12^2}}\sqrt{\frac{73^2-1}{73^2}}\\

=\frac{73}{12}\sqrt{1 - \frac{1}{73^2}} \\

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5 0
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Sum of two number is 120. If the larger number is four times the smaller number, wbat are the two numbers
tankabanditka [31]

x+y=120_______1

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3 0
3 years ago
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