Answer:b 27 feet
Step-by-step explanation:You need a ladder that will reach up a 25 foot tall house when placed 10 feet away from the house.
Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Answer:
26%
Step-by-step explanation:
Subtract the old amt from the new amt, then divide by the old amt:
19-15/15 = 4/15 = 26.6%. Rounded to the nearest tenth it would be 26%.
The equation 44 - x + 2x = 50 can be used to determine the number of cats/kittens adopted.
Step-by-step explanation:
Given,
Number of cats/kittens at the event = 44
Number of cats/kittens at the end of event = 50
Let,
x be the number of cats/kittens adopted
Therefore;
Number of cats/kittens returned = 2x
Number of cats/kittens at the event - adopted + returned = Number at the end of event
44 - x + 2x = 50
The equation 44 - x + 2x = 50 can be used to determine the number of cats/kittens adopted.
Keywords: equation, variable
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