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kykrilka [37]
3 years ago
10

If x=-24and y=6 what is the value of the expression |x+y|

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
8 0

Answer:

-18,18

Step-by-step explanation:

|-24+6|= -18

and also 18 because of absolute value.

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WRITE POLYNOMIAL INSTANDARD FORM<br> -9X4+2X-1
Harrizon [31]

Answer:

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Step-by-step explanation:

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3 years ago
If 37 represents an increase of 37, what does -37 represents
Genrish500 [490]
Probs a decrease of 37 boiiii
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4 years ago
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BD bisects m m Find m
amm1812

The text of the question is not visible in the answering window. I'll reproduce it here:

BD bisects <ABC.

m <ABD= 2.5x + 8.6

m<CBD = 3.5x - 3.4

Find m<ABC

Answer:

m\angle ABC = 77.2^\circ

Step-by-step explanation:

We have an angle ABC and a line BD bisecting it.

If an angle is bisected, then the two formed angles are congruent, that is

m\angle ABD=m\angle CBD

Substituting the algebraic expressions for both angles:

2.5x + 8.6=3.5x - 3.4

Subtracting 8.6 and 3.5x:

2.5x - 3.5x = -8.6 - 3.4

Operating:

-x = -12

x = 12

The two angles are:

m\angle ABD=2.5x + 8.6=2.5(12) + 8.6=38.6^\circ

m\angle CBD=3.5x - 3.4 = 38.6^\circ

As expected, both angles have the same measure.

The measure of the total angle ABC is twice any of those:

m\angle ABC = 2*38.6^\circ=77.2^\circ

\mathbf{m\angle ABC = 77.2^\circ}

6 0
3 years ago
Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

What is the probability that they are both queens?

P = \frac{D}{T} = \frac{6}{1326} = 0.0045

0.45% probability that they are both queens.

4 0
3 years ago
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elena-14-01-66 [18.8K]

Answer:

30? lol im guessing? idk...lol

Step-by-step explanation:

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