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mojhsa [17]
3 years ago
14

How do you write 4 to the 2ND power in standard notation

Mathematics
1 answer:
romanna [79]3 years ago
6 0
4 to the second power in standard notation is 400/1.
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If the ceos salary of 1,000,000 is taken out of the list what I would happen to the mean and median 25,25,25,35,35,45,45,55,55
Mama L [17]

Answer:

Both the mean and median decrease.

Step-by-step explanation:

Median (without 1,000,000):

<em>25, 25, 25, 35</em>, 35,<em> 45, 45, 55, 55</em>

= 35

Median (with 1,000,000):

<em>25, 25, 25, 35</em>, 35, 45, <em>45, 55, 55, 1,000,000</em>

= average of 35 and 45

= 40

As you can see, without the outlier, the value of the median decreases.

Mean (without 1,000,000):

= (25 + 25 + 25 + 35 + 35 + 45 + 45 + 55 + 55) / 9

= 38.3

Mean (with 1,000,000):

= (25 + 25 + 25 + 35 + 35 + 45 + 45 + 55 + 55 + 1,000,000) / 10

= 100,0034.5

As you can see, without the outlier, the value of the mean dramatically decreases.

6 0
2 years ago
What is 2.05 +4.77 ?
Effectus [21]

The answer is 6.82

2 + 4 = 6

.05 + .77 = .82

6 + .82  = 6.82

4 0
2 years ago
Read 2 more answers
Please help :,( .....
Vladimir79 [104]
the 4th term is 58
7 0
3 years ago
Read 2 more answers
What are the inputs of the following function?
igor_vitrenko [27]

Answer:

  A. {-4, -3, 7, 8}

Step-by-step explanation:

The ordered pairs representing a function are always written ...

  (input, output)

<h3>Inputs</h3>

The set of inputs for the given function is the list of first-numbers of the ordered pairs. Those numbers are -3, -4, 8, 7. When we express them as a set, we like to have the elements of the set in increasing order:

  inputs = {-4, -3, 7, 8} . . . . . . matches the first choice

7 0
2 years ago
A deck of playing cards has four suits, with thirteen cards in each suit consisting of the numbers 2 through 10, a jack, a queen
vekshin1
Since order does not matter, you use a combination and not a permutation, so the first one is true, which means the second one is not true.
The probability of choosing two diamonds and three hearts can be represented by (13C2 * 13C3)/52C5, which is 0.0086, not 0.089, so the third one is not true.
The probability of choosing five spades and the probability of choosing five clubs are represented by the same thing, 13C5/52C5, which is roughly 0.0005, so the fourth one is not true but the fifth one is. So the answer is the first and fifth one.

4 0
3 years ago
Read 2 more answers
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