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Feliz [49]
3 years ago
11

I wish I can give out more points but I'm lacking on points myself, so sorry! thank you for anyone who puts their time into help

ing me :-D (even answering one of the three questions are a big help for me!)

Mathematics
1 answer:
Lena [83]3 years ago
7 0
Well I'm still trying to solve the first question so I'll tell you the other answers
the answer for the second question is :
{4x}^{2}  + 20x
and for the third question :
\frac{7}{8}
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2(vh)/k=r Solve equation for v in terms of all other variables involved
aivan3 [116]

The equation v in terms of other variables is v = kr/2h

<h3>What is the subject of an equation?</h3>

It is a variable which is expressed in terms of other variables involved in the formula.

Formulas are written so that a single variable, the subject of the formula is on the L.H.S. of the equation. Everything else goes on the right side of the equation. We evaluate the formula by substituting for the literal numbers on the right hand side.

2(vh) / k = r

by cross multiplication

2(vh) = kr

divide both sides by 2h

v = kr/2h

In conclusion, v in terms of other variables is  kr/2h

Learn more about subject of an equation: brainly.com/question/657646

#SPJ1

6 0
1 year ago
Solve for x: 2/3+1/3x=2x
velikii [3]

Answer:

x=2/5 or

x=0.4

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A cube with an edge of length has a volume of 64 units. What is the length of ? Hint: Volume of a cube is LxWxH.
aleksandr82 [10.1K]

Answer:

it is 4

Step-by-step explanation:

5 0
3 years ago
Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis. Verify y
mariarad [96]

Answer:

the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

\frac{\pi }{2}  [e^2 - 1 ]  or 10.036

Step-by-step explanation:

Given the data in the question;

y = y = e^{(x - 1 ), y = 0, x = 1, x = 2.

Now, using the integration capabilities of a graphing utility

y = y = e_2}^{(x - 1 )_, y = 0

Volume = \pi \int\limits^2_1 ( e^{x-1)^2} - (0)^2 dx

Volume = \pi \int\limits^2_1 ( e^{x-1)^2  dx

Volume = \pi \int\limits^2_1 e^{2x-2}dx

Volume = \frac{\pi }{e^2} \int\limits^2_1 e^{2x}dx

Volume = \frac{\pi }{e^2}  [\frac{e^{2x}}{2}]^2_1

Volume = \frac{\pi }{2e^2}  [e^4 - e^2 ]  

Volume = \frac{\pi }{2}  [e^2 - 1 ]  or 10.036

Therefore, the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

\frac{\pi }{2}  [e^2 - 1 ]  or 10.036

   

3 0
3 years ago
Choose what of the of are a rectangle choose all the answers !!!!!!
alekssr [168]

Answer:

...

Step-by-step explanation:

bottom left and the square and the parallelogram(top right)

A parallelogram is a rectangle.

8 0
3 years ago
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