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KengaRu [80]
3 years ago
5

The graph of y=x^3 is transformed as shown below?

Mathematics
2 answers:
Anastasy [175]3 years ago
8 0
Y= -2x^3 is the answer
Hope this helps!
USPshnik [31]3 years ago
8 0

Solution:

A

Step-by-step explanation:

It's y =-2x³

<em>Hop</em><em>e</em><em> </em><em>it</em><em> </em><em>h</em><em>elps</em><em> </em><em>y</em><em>ou</em><em>.</em><em>.</em><em>☺</em>

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The time needed to complete a final examination in a particular college course is normally distributed with a mean of 77 minutes
Komok [63]

Answer:

a. The probability of completing the exam in one hour or less is 0.0783

b. The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. The number of students will be unable to complete the exam in the allotted time is 8

Step-by-step explanation:

a. According to the given we have the following:

The time for completing the final exam in a particular college is distributed normally with mean (μ) is 77 minutes and standard deviation (σ) is 12 minutes

Hence, For X = 60, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=60−77 /12

Z=−1.4167

Using the standard normal table, the probability P(Z≤−1.4167) is approximately 0.0783.

P(Z≤−1.4167)=0.0783

Therefore, The probability of completing the exam in one hour or less is 0.0783.

b. In this case For X = 75, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=75−77 /12

Z=−0.1667

Using the standard normal table, the probability P(Z≤−0.1667) is approximately 0.4338.

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is obtained as follows:

P(60<X<75)=P(Z≤−0.1667)−P(Z≤−1.4167)

=0.4338−0.0783

=0.3555

​

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. In order to compute  how many students you expect will be unable to complete the exam in the allotted time we have to first compute the Z−score of the critical value (X=90) as follows:

Z=  X−μ /σ

Z=90−77 /12

Z​=1.0833

UsING the standard normal table, the probability P(Z≤1.0833) is approximately 0.8599.

Therefore P(Z>1.0833)=1−P(Z≤1.0833)

=1−0.8599

=0.1401

​

Therefore, The number of students will be unable to complete the exam in the allotted time is= 60×0.1401=8.406

The number of students will be unable to complete the exam in the allotted time is 8

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Which value lies between 8 and 9 on a number line?
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The answer is root 70
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determine the equation of the straight line which passes through the point 1 and 5 and is perpendicular to the line 3x + y is eq
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The straight line is perpendicular to y = -3x + 4.

Therefore, the gradient of the straight line must be 3.

The equation of the straight line is y = 3x + 2.

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Your family is having a family reunion and you are in charge of the food, there are two great restaurants, but you must choose o
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