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kramer
3 years ago
13

Joshua has (10+6a^2-5a) dollars in his savings account. Maranda had (4a^2a+3) dollars in her saving account how much more money

does Joshua have than maranda?
Mathematics
2 answers:
Ulleksa [173]3 years ago
4 0

Given Information:

We are given two polynomial equations which represents the amount of savings in dollars

Joshua's savings = 6a² - 5a + 10 dollars

Maranda savings = 4a² + a + 3 dollars  (assuming +a since the sign is missing in the question)

Required Information:

How much more money does Joshua have than Maranda = ?

Answer:

Joshua has 2a² - 6a + 7 dollars more than Maranda

Step-by-step explanation:

We can subtract the amount of savings of Maranda from the amount of savings of Joshua, and we will get the excess amount of savings that Joshua has.

Joshua = 6a² - 5a + 10 dollars

Maranda = 4a² + a + 3 dollars

Excess = 6a² - 5a + 10 - (4a² + a + 3)

change the sign of terms

Excess = 6a² - 5a + 10 - 4a² - a - 3

combine the like terms

Excess = (6a²-4a²)  (-5a-a)  (+10-3)

Excess = 2a² - 6a + 7

Therefore, Joshua has 2a² - 6a + 7 dollars more than Maranda.

solniwko [45]3 years ago
3 0

Answer:

Joshua has 2a^2 -6a + 7 more than Maranda.

Step-by-step explanation:

Joshua has 6a^2 -5a + 10 dollars and Maranda has 4a^2 + a + 3 to find out how much more money Joshua has we need to subtract the amount he has by the amount of Maranda's account. Since both expressions are pollynomial we'll have to subtract the numbers wich are multiplying the same power, so we do as follow:

6a^2 - 5a + 10 - (4a^2 + a + 3)

6a^2 - 5a + 10 - 4a^2 -a -3

6a^2 - 4a^2 -5a -a + 10 -3

2a^2 -6a + 7

Joshua has 2a^2 -6a + 7 more than Maranda.

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Step-by-step explanation:

3 0
3 years ago
Amelia, Luis, Shauna, and Clarence used different approaches to solve the inequality 7.2b + 6.5 > 4.8b – 8.1. Which student's
Aleks [24]

Answer: Luis’s, because he flipped the inequality sign when he subtracted

Step-by-step explanation:

Here is the complete question:

Amelia, Luis, Shauna, and Clarence used different approaches to solve the inequality

7.2b + 6.5 > 4.8b – 8.1.

Amelia started by subtracting 7.2b from both sides to get 6.5 > –2.4b – 8.1.

Luis started by subtracting 4.8b from both sides to get 2.4b + 6.5 < – 8.1.

Shauna started by subtracting 6.5 from both sides to get 7.2b > 4.8b – 14.6.

Clarence started by adding 8.1 to both sides to get 7.2b + 14.6 > 4.8b.

Which student’s first step was incorrect, and why?

a. Amelia’s, because the variable term must be isolated on the left side

b. Luis’s, because he flipped the inequality sign when he subtracted

c. Shauna’s, because she did not apply the subtraction property of equality properly.

d. Clarence’s, because the terms he added together were not like terms.

The inequality given is:

7.2b + 6.5 > 4.8b – 8.1.

We are informed that Luis started by subtracting 4.8b from both sides to get 2.4b + 6.5 < – 8.1.

If Luis started by subtracting 4.8b from both sides, he should get:

7.2b + 6.5 > 4.8b – 8.1.

7.2b + 6.5 - 4.8b > 4.8b – 8.1 - 4.8b

2.4b + 6.5 > - 8.1

But looking critically, we would realise that what Luis got us different as the inequality sign has been changed from greater than to less than and this is incorrect.

The inequality sign can only be flipped in case whereby there's a division or multiplication of a negative number from both sides.

Therefore, Luis’s first step was incorrect because he flipped the inequality sign when he subtracted.

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y = -4+7/2x

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x = -4 +7/2y

Solve for y

Add 4 to each side

x+4 = -4+4 +7/2y

x+4 = 7/2y

Multiply each side by 2/7

2/7(x+4) = 2/7 * 7/2y

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