Question

Dakota knows that EJ←→⊥CN←→ and CN←→∥KT←→ .

Answer 1

Given that line EJ is perpendicular to line CN and line CN is parallel to line KT.

Since E, J and V is collinear (are on the same straight line), thus EV is perpendicular to CN, and since CN is parallel to KT, thus EV is perpendicular to KT.

Since line C, J and N are collinear and CN is perpendicular to EJ, this means that line CN and line EJ meets at point J and since they are perpendicular, <CJV = 90 degrees.

Therefore, the correct answers are:

EV←→⊥KT←→
and
m∠CJV=90°