The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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It looks to be 29, if the rule is to add 3z
The vertex of the quadratic equation is (-5, - 28). In vertex form, y = a(x - h)2<span> + </span><span>k, (h, k) is the vertex of the equation.</span>
Answer:
It is $46 per video game because 92 divided by 2 is 46.
Step-by-step explanation:
Given coordinates of the triangle RST are R(2,1), S(2,-2) and T(-1,-1).
Center of center of dilation is (2,-2).
Because center of dilation is (2,-2) so the coordinates of dilated image S(2,-2) would stay same.
Now, we need to apply rule for dilation with the scale factor 5/3.
Each of R(2,1), and T(-1,-1) would be and R' and T' would be in ratio 5/3.
We will extend RS to 5 units and TS also 5 units.
The new resulting image would be dilated triangle by a scale factor 5/3.