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SpyIntel [72]
3 years ago
12

Please help me on this , Thank you

Mathematics
1 answer:
aliina [53]3 years ago
3 0
I think it is b I think I’m right
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A new truck that sells for 25,000 (decreases in value) 11% each year. what will be the value of the truck in two years?
True [87]
$19,802.5  I hope this helps and I'm sorry I didn't reply sooner.
4 0
3 years ago
How do u do this problem: W/6+5/8=-1 3/8 <br> I got this answer: -1 53/64
Kobotan [32]
We have question
\frac{W}{6}+ \frac{5}{8} =-1 \frac{3}{8}    
\frac{W}{6} + \frac{5}{8} =- \frac{11}{8}  <span> /*8      (multiply both sides by 8)</span>
\frac{W8}{6} + \frac{5}{1} =- \frac{11}{1}  /*6      (multiply both sides by 6)
8W+5*6=-11*6      /-30 both sides
8W=-66-30
8W=-96
W=-12
6 0
3 years ago
Read 2 more answers
If 10% of men are bald, what is the probability that fewer than 100 in a random sample of 818 men are bald? (Answers must be in
Greeley [361]

Answer: the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830

Step-by-step explanation:

Given that;

p = 10% = 0.1

so let q = 1 - p = 1 - 0.1 = 0.9

n = 818

μ = np = 818 × 0.1 = 81.8

α = √(npq) = √( 818 × 0.1 × 0.9 ) = √73.62 = 8.58

Now to find P( x < 100)

we say;

Z = (X-μ / α) = ((100-81.8) / 8.58) = 18.2 / 8.58 = 2.12

P(x<100) = P(z < 2.12)

from z-score table

P(z < 2.12) = 0.9830

Therefore the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830

4 0
3 years ago
Starting with the number 3, build a sequence of 5 numbers.
just olya [345]

Answer:

3, 6, 9, 12, 15

adding 3 each time

or

3, 9, 27, 81, 243

multiplying by 3 each time

Step-by-step explanation:

8 0
3 years ago
A spinner marked A, B, C is spun then a 6-sided die is rolled. What is the probability of getting a B and then a 6.
BigorU [14]

Given:

A spinner marked A, B, C is spun then a 6-sided die is rolled.

To find:

The probability of getting a B and then a 6.

Solution:

We know that,

\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

Total possible values for a spinner are 3. So, the probability of getting B, we get

P(B)=\dfrac{1}{3}

Total possible values for a die are 6. So, the probability of getting 6, we get

P(6)=\dfrac{1}{6}

Now, the probability of getting a B and then a 6 is

P(B,6)=\dfrac{1}{3}\times \dfrac{1}{6}

P(B,6)=\dfrac{1}{18}

The required probability is \dfrac{1}{18}.

Therefore, the correct option is D.

5 0
3 years ago
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