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Romashka [77]
4 years ago
6

Solve for x 3= x/2 pls i need this ASAP

Mathematics
1 answer:
yawa3891 [41]4 years ago
8 0

Answer:x = 1.5

Step-by-step explanation:

3 = x / 2

First get rid of / 2

3/2 = 1.5

:D

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labwork [276]

1.

rational numbers are numbers that can be written in form a/b where a and b are integers (-4,-3,-2,-1,0,1,2,3, etc) and b isn't 0


so for case \frac{a}{b}+\frac{c}{d}

we need to make the denomenators the same

so for \frac{a}{b}+\frac{c}{d}, multiply left one by d/d and multiply right one by b/b to get

\frac{ad}{bd}+\frac{cb}{bd}=\frac{ad+cb}{bd}

therefore \frac{a}{b}+\frac{c}{d}=\frac{ad+cb}{bd}[/tex] is the rule




2. do the same as previous but do minus

so for case \frac{a}{b}-\frac{c}{d}

we need to make the denomenators the same

so for \frac{a}{b}-\frac{c}{d}, multiply left one by d/d and multiply right one by b/b to get

\frac{ad}{bd}-\frac{cb}{bd}=\frac{ad-cb}{bd}

therefore \frac{a}{b}-\frac{c}{d}=\frac{ad-cb}{bd}[/tex] is the rule




3. not sure, I hope this is right

so for case \frac{a}{b}+\frac{c}{d}=0

we need to make the denomenators the same

so for \frac{a}{b}+\frac{c}{d}, multiply left one by d/d and multiply right one by b/b to get

\frac{ad}{bd}+\frac{cb}{bd}=\frac{ad+cb}{bd}=0

if we multiply both sides by bd we get

ad+cb=0

therefore, ad=-cb for the sum to always equal 0




4.  

(\frac{a}{b})(\frac{c}{d})=1

\frac{ac}{bd}=1

multiply both sides by bd

ac=bd for the product of the 2 fractions to equal 1

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Use substitution to solve this system of equations. 4x-5y=19 y=8x-11
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4x-5y=19 \\
y=8x-11 \\ \\
\hbox{substitute 8x-11 for y in the 1st equation and solve for x:} \\
4x-5(8x-11)=19 \\
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4x-40x=19-55 \\
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x=\frac{-36}{-36} \\
x=1 \\ \\
\hbox{substitute 1 for x in one of the equations and solve for y:} \\
y=8 \times 1-11 \\
y=8-11 \\
y=-3 \\ \\
(x,y)=(1,-3)
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