1+tan^2(A) = sec^2(A) [Pythagorean Identities]
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*
Answer:
3/12: terminating; 2/9: repeating
Step-by-step explanation:
3/12=0.25 terminating as it has a finite number of digits after the decimal point.
2/9=0.222.... repeating decimal as its number is repeated indefinitely.
Answer:
All the conditions for the chi square test of homogeneity are satisfied.
Step-by-step explanation:
The conditions for the chi square test are
1) the sample is a random sample
2) the variable under study is categorical
3) all expected value of the number of sample observations are greater or equal to 5.
A)The observations must be independent
B) for 2 categories the expected values must be at least 5
C) for the 3 categories the expected values must be at least 1 and no more than 20% may be smaller than 5
The observations given are independent that is not equally likely i.e do not have equal chances of occurrences or are not dependent on each other.
4) the overall sample must be resonably large that is greater than 50
Answer:
$28
Step-by-step explanation:
Given that:
Value of Winning bid = $52
Winning bid 65% of the maximum bid.
To find:
How much more is the maximum bid from the winning bid ?
Solution:
We are given that the winning bid is 65% of the maximum bid.
Using this percentage value, we need to first find the value of maximum bid and then we need to subtract the value of winning bid from the maximum bid to find the answer.
Let the value of maximum bid = $
As per question statement:

Therefore, maximum bid = $80
Our answer is:
$80 - $52 = <em>$28</em>
Answer:
x=3
y=5
Step-by-step explanation:
x+5y=28 (i)
-x-2y=-13. (ii)
add equation 2 from equation 1
x+5y=28
-x-2y=-13
3y=15
y=5
put the value of y in equation 1
x+5y=28
x+5*5=28
x+25=28
x=28-25
x=3