Answer:
7 years 11 months
Step-by-step explanation:
The future value formula for the value of a principal P invested at annual rate r compounded n times yearly for t years is ...
FV = P(1 +r/n)^(nt)
For the given numbers, we want to find t:
6000 = 3700(1 +.062/2)^(2t)
Dividing by 3700 and taking the logarithm, we get ...
6000/3700 = 1.031^(2t)
log(60/37) = 2t·log(1.031)
Dividing by the coefficient of t gives ...
t = log(60/37)/(2log(1.031)) ≈ 7.92 . . . . . years
It will take about 7 years 11 months for the investment to grow to $6000.
X+23=-22
-23 -23
x=-45
a+(-1.3)=-4.5
or
a-1.3+-4.5
+1.3 +1.3
a=3.2
Answer:
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Step-by-step explanation:
Answer:
$712.
Step-by-step explanation:
We have been given that a fund earns a nominal rate of interest of 6% compounded every two years. We are asked to find the amount that must be contributed now to have 1000 at the end of six years.
We will use compound interest formula to solve our given problem.
, where,
A = Final amount,
P = Principal amount,
r = Annual interest rate in decimal form,
n = Number of times interest is compounded per year,
t = Time in years.
Since interest is compounded each two years, so number of compounding per year would be 1/2 or 0.5.
Therefore, an amount of $712 must be contributed now to have 1000 at the end of six years.
Answer:
49
Step-by-step explanation:
64- 15 = 49
Hope that this helps you and have a great day
