Answer:
Approximately 3 grams left.
Step-by-step explanation:
We will utilize the standard form of an exponential function, given by:
In the case of half-life, our rate <em>r</em> will be 1/2. This is because 1/2 or 50% will be left after <em>t </em>half-lives.
Our initial amount <em>a </em>is 185 grams.
So, by substitution, we have:
Where <em>f(t)</em> denotes the amount of grams left after <em>t</em> half-lives.
We want to find the amount left after 6 half-lives. Therefore, <em>t </em>= 6. Then using our function, we acquire:
Evaluate:
So, after six half-lives, there will be approximately 3 grams left.
Answer:
(71 301 952, 19 999 328)
Step-by-step explanation:
sana makatulong
Answer:
7
Step-by-step explanation:
Answer:
363
Step-by-step explanation:
11x11=121
((11x11)÷2)x4=11x11x2=121x2=242
121+242=363
1/6
Step-by-step explanation:
- According to the question, the right combination of 2 wires cut (out of the 4 wires ) will defuse the bomb. To find all the possible combinations we using the following formulae;
nCr = n! / r! * (n - r)!
⁴₂C = 4! / 2! * (4-2)!
⁴₂C = 24 / 2 * 2
⁴₂C = 6
- There are a possible 6 combinations
- Therefore for probability of cutting the right combination of 2 wires is 1/6
Learn More:
To learn more about combinations check out;
brainly.com/question/3374511
brainly.com/question/3901018
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